Hello there ^ _ ^
I'm gonna just try my best for this thing :)
log6x + log6(x+5) = 2
1.556303x + 3.890756 = 2
1.556303x = 2 - 3.890756
1.556303x = 1.890756
Divide both sides by 1.556303
1.556303x/1.556303 = 1.890756/1.556303
x = -1.214902
So the potential solution is x = -1.21
I hope this help! I just tried my best :)
Answer:
I think the answer for this question is C
For the 1st hour the cost is $50 whatever is the duration (providing it's 1 hour max.
From one hour and onward the cost becomes an additional $25 per quater of an hour.
If y is the cost and x the number of hours, then the equation becomes :
y =50 + 0.25.x or y =1/4x + 50
The formula for the area of a square is A = s^2, where s is the side length. Here, 225 cm^2 = s^2.
To find the side length, we need only take the sqrt of both sides of this equation and eliminate the negative root:
plus or minus √{225 cm^2) = s. Thus, s = 15 cm = side length.
Answer: Large box 1 can hold 64.67 inches; Large box 2 can hold 56.19 inches.
Step-by-step explanation:
Small box: 162 inches.
Large box 1: 10476 inches.
Large box 2: 9102 inches
Number of small box that can be contained in large box 1= 10476/162 = 64.67
Number of small box that can be contained in large box 2 = 9102/162 = 56.19
If my friend uses division to determine and said Large Box 1 can hold 64 small boxes and Large box 2 can hold 56 small boxes. The error in his reasoning was that he didn't approximated to whole number. He should have written the figure completely or to 2 or 3 decimal places.