Answer:
- asymptotes: x = -5, x = 5
- zero: x = 0
Step-by-step explanation:
The function of interest is ...
The asymptotes are found where the denominator is zero. It will be zero when either factor is zero, so at x = 5 and x = -5
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The zeros are found where the numerator is zero. It will be zero for x = 0.
The asymptotes are x=-5, x=5; the zero is x=0.
6²+8²=c²
36+64=c²
c²=100
c=10
I HOPE IT WILL HELP YOU. I DID HOW I KNOW .
What is being solved for is r.
we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.
<h3>What is the last digit of the product of all the numbers between 11 and 29?</h3>
Here we want to find the last digit of the product between all the whole numbers larger than 11 and smaller than 29.
Then we have the product:
P = 12*13*14*15*16*17*18*19*20*21*22*23*24*25*26*27*28
Now, notice that there is a 20 there.
Any number times 20 will end with a zero, then:
P = 20*(12*13*14*15*16*17*18*19*21*22*23*24*25*26*27*28)
Only with that, we can conclude that the last digit of the product of all the numbers between 11 and 29 is 0.
If you want to learn more about products:
brainly.com/question/10873737
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