Answer:
{x = 2 , y = -2
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
{y = x/2 - 3 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
{-x/2 + y = -3 | (equation 2)
Add 1/6 × (equation 1) to equation 2:
{3 x + y = 4 | (equation 1)
{0 x+(7 y)/6 = (-7)/3 | (equation 2)
Multiply equation 2 by 6/7:
{3 x + y = 4 | (equation 1)
{0 x+y = -2 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 6 | (equation 1)
{0 x+y = -2 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 2 | (equation 1)
{0 x+y = -2 | (equation 2)
Collect results:
Answer: {x = 2 , y = -2
<u>Answer</u>:
Jared is right.
<u>Explanation</u>:
proof 1:
10 - 4 = 6
6 = 6
second proof:
10-3 - 4 = 6 - 3
10 - 7 = 3
3 = 3
third proof:
10 - 4 - 3 = 6 - 3
10 - 7 = 3
3 = 3
Hence for all LHS = RHS proved and Jared is correct.
Answer:
T F → F
Step-by-step explanation:
2+2 does equal 4 so its true.
but 7+1 does <em>not</em><em> </em>equal 7, it equals 8. So its fasle.
im not sure i did this this right so if i did it wrong im sorry love (-ω-；)
