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Sonja [21]
3 years ago
13

Consider the squence following a minus 8 pattern 9,1,-7,-15 write an explict formula for the squence

Mathematics
1 answer:
Andrew [12]3 years ago
7 0
A(x) = 17 - 8x. Hope this helps!
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(4y^2)^3(3y^2) Please help :)
Ierofanga [76]

Answer:

192y^8

Step-by-step explanation:

7 0
3 years ago
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What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?
mars1129 [50]
The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2

the sum of a geometric seequence is
S_{n}=\frac{a_{1}(1-r^{n})}{1-r}
a1=1
r=2
we want to find S_{10} (since we minus 1, the highest exponet is 9 so add 1 to make it correct)

S_{10}=\frac{1(1-2^{10})}{1-2}
S_{10}=\frac{(1-1024}{-1}
S_{10}=\frac{(-1023}{-1}
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3 years ago
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What is 55x690-20+438x129=? <br> I will give brainliest.
frosja888 [35]

Answer:

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7 0
3 years ago
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Which of the numbers below could be terms in the sequence an=7n +4?<br> 24<br> 46<br> 32<br> 36
mrs_skeptik [129]

Answer:

46

Step-by-step explanation:

46 - 4 = 42

42/7 = 6

7 0
3 years ago
a family has five children. the probability of having a girl is 1/2. whats probability of having at leasr 4 girls g'
Dima020 [189]

Answer:

Probability of having at least 4 Girls

= 0.6875

Step-by-step explanation:

Probability of having at least 4 Girls is 1-probability of having exactly 3 girls

Total number of children= 5 = N

Probability of having a girl p = 0.5

Probability of not having a girl q= 0.5

X= 3

Probability of at least 4 girls is given by

Probability= NCX(p)^x(q)^(N-x)

Probability = 5C3(0.5)^3(0.5)^(5-3)

Probability = 5C3(0.5)^3(0.5)^2

Probability= 5!/3!2!(0.5)^3(0.5)^2

Probability= 10(0.125)(0.25)

Probability= 0.3125

Probability of having at least 4 Girls

= 1- 0.3125

= 0.6875

7 0
3 years ago
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