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valentinak56 [21]
3 years ago
12

Given that the straight line 2x + 3y-10=0 intersects the x - axis at P. Find the

Mathematics
1 answer:
tino4ka555 [31]3 years ago
3 0

Answer:

P(5, 0 )

Step-by-step explanation:

Where the line crosses the x- axis the y- coordinate of the point P is zero.

Substitute y = 0 into the equation and solve for x

2x + 3(0) - 10 = 0 , that is

2x - 10 = 0 ( add 10 to both sides )

2x = 10 ( divide both sides by 2 )

x = 5

Thus P = (5, 0 )

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For question 1, the largest value would be 1 and the smallest value would be -1. A, B, and C are either all 1 or two is negative and one is positive, either way the number is 1 and it's opposite. 1^2 is 1, 1^3 is 1, 1^4 is 1. The product is 1. -1^2 is -1, -1^3 is -1, -1^4 is -1. The product is -1. Now the difference. 1 - (-1), which is 1 + 1, the answer is [D) 2]
4 0
3 years ago
Gina is painting the rectangular tool chest shown in the diagram
Nikitich [7]

Answer:

2,880

Step-by-step explanation:

24X12X10=2,880

<em>Hopes This Helps :)</em>

6 0
3 years ago
If your starting salary were $40,000 and you received a 3% increase at the end of every year for 15 years, what would be the tot
Dmitry [639]

T = 40000 + 40000(1.03) + 40000(1.03)^2 + ... + 40000(1.03)^15


Multiply the above equation by 1.03 giving


1.03(T) = 40000(1.03) + 40000(1.03)^2 + 40000(1.03)^3 + ... + 40000(1.03)^15 + 40000(1.03)^16


Now subtract the first equation from the second to give


0.03T = 40000(1.03)^16 - 40000


0.03T = 40000(1.03^16 - 1)


0.03T = 24188.26


T = 24188.26 / 0.03 = $806275.25


6 0
3 years ago
Read 2 more answers
Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen
boyakko [2]
PART A
s = <span>the number of packets of strawberry wafers ;
c = </span><span>the number of packets of chocolate wafers ;
3 </span>× s + 1 × <span>c = 30 ;
s + c = 22 ;

PART B

</span>The method of solving "by substitution"<span> works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
</span>
c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;

4 0
3 years ago
Step 1: [($52.65 ⋅ 5) + $46.25 − $16.25] ⋅ 1 over 6
Goshia [24]
[ (52.65 * 5) + 46.25 - 16.25] * 1/6
[ 263.25 + 46.25 - 16.25] * 1/6
293.25 * 1/6 =
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48.875

error occurred in step 3....he multiplied by 6 instead of multiplying by 1/6
4 0
3 years ago
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