Answer:
16
Step-by-step explanation:
3^3=27 then you have 27+13=40 now you have 56-40=16
A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
Answer:
y = 0.5sin(4x)
Step-by-step explanation:
y = A sin(B(x + C)) + D
amplitude is A = 0.5
B = 2π/period = 2π / (1/2 π) = 4
phase shift is C (positive is to the left) = 0
vertical shift is D = 0
Answer:
C) S = {F, PF, PPF, PPP}
Step-by-step explanation:
For this case, we know that a person is trying to gain access to a bank vault and needs to go through 3 security doors, and we know that if the person does not pass a door, then he/she has no other attempts. We denote P= Successful pass , F= Failed pass
And we are interested on the sample space, we need to remember that the sample is the set with all the possible values for an experiment.
For this case the person can fail at the 1,2 or 3 try
For the case that fails at the 1 try we have F
For the case that fails at the 2 try we have PF
For the case that fails at the 3 try we have PPF
And the last option is that the person not fails at any try and we have PPP
So then the sample space would be given by:
C) S = {F, PF, PPF, PPP}
Answer:
No, I don't think so.
Step-by-step explanation:
If his suitcase weighs 23 kg and 10 kg is 22 pounds. You could seperate it. 10, 10, and 3 meaning 22+22= 44. This would mean that 1 kg would equal about 2.2 a pound. So 44 + ( 2.2 x 3 ) = 50.6 kg.
It would be 0.6 k.g over. I think this is right unless I calculated this wrong.
