Answer:
Between 150 and 450
Step-by-step explanation:
We are going to find the number by resolving a system of linear equations.
First we write the system equations :
![C+S+A=750](https://tex.z-dn.net/?f=C%2BS%2BA%3D750)
Where C : children, S : students and A : adults
The equation represents the ''full attendance''
The second equation :
![3C+5S+7A=3450](https://tex.z-dn.net/?f=3C%2B5S%2B7A%3D3450)
This equation represents the totaled receipts.
The system :
![C+S+A=750\\3C+5S+7A=3450](https://tex.z-dn.net/?f=C%2BS%2BA%3D750%5C%5C3C%2B5S%2B7A%3D3450)
has the following associated matrix :
![\left[\begin{array}{cccc}1&1&1&750\\3&5&7&3450\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%261%261%26750%5C%5C3%265%267%263450%5Cend%7Barray%7D%5Cright%5D)
By performing elementary matrix operations we find that the matrix is equivalent to
![\left[\begin{array}{cccc}1&0&-1&150\\0&1&2&600\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-1%26150%5C%5C0%261%262%26600%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The new system :
![C-A=150\\S+2A=600](https://tex.z-dn.net/?f=C-A%3D150%5C%5CS%2B2A%3D600)
Working with the equations :
![C = 150 + A\\S = 600-2A](https://tex.z-dn.net/?f=C%20%3D%20150%20%2B%20A%5C%5CS%20%3D%20600-2A)
Our solution vector is :
![\left[\begin{array}{c}C&S&A\end{array}\right] =\left[\begin{array}{c}150+A&600-2A&A\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7DC%26S%26A%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D150%2BA%26600-2A%26A%5Cend%7Barray%7D%5Cright%5D)
For example :
If 0 adults attended ⇒ A = 0
![C = 150 + 0 \\C = 150\\S = 600 - 2A\\S = 600](https://tex.z-dn.net/?f=C%20%3D%20150%20%2B%200%20%5C%5CC%20%3D%20150%5C%5CS%20%3D%20600%20-%202A%5C%5CS%20%3D%20600)
This verify the totaled receipts equation :
150($3)+600($5) = $ 3450
A ≥ 0 ⇒ If A = 0 ⇒ C = 150
C = 150 is the minimum children attendance
From the equation :
![S = 600 -2A](https://tex.z-dn.net/?f=S%20%3D%20600%20-2A)
S ≥0
600 - 2A ≥ 0
600 ≥ 2A
300≥ A
A is restricted to the interval [ 0, 300]
When A = 0 ⇒ C = 150
When A = 300 ⇒C = 150 + A = 150 + 300 = 450
Children ∈ [ 150,450]
With C being an integer number (including 0)
Also S and A are integer numbers (including 0)