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3 years ago

96 people have been invited to a banquet each table table can seat 12 people how many tables do you need

Mathematics

2 answers:

Tasya [4]3 years ago

7 0

Answer:

You would need 8 tables

Step-by-step explanation:

96/12

EleoNora [17]3 years ago

3 0

96/12 = 8
You need 8 tables

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$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

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3 years ago

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4 years ago

96 people have been invited to a banquet each table table can seat 12 people how many tables do you need ​

96 people have been invited to a banquet each table table can seat 12 people how many tables do you need