Answer:
There will be 94.7 grams of krypton gas
Explanation:
<u>Step 1:</u> Data given
at 255K and 0.750 atm the volume is 3.75 L
At 1.25 atm the volume is 2.55 L
Molar mass of krypton = 83.798 g/mol
<u>Step 2</u>: Calculate number of moles
p*V = n*R*T
with p = the pressure of the krypton gas = 0.750 atm
with V = the volume of the krypton gas = 3.75 L
with n = the number of moles = TO BE DETERMINED
with R = the gasconstant = 0.08206 L*atm/ mol * K
with T = the temperature = 255 K
n = R*T / p*V
n = (0.08206 * 255)/ (0.750 * 3.75)
n = 0.744 moles
<u>Step 3:</u> Calculate new number of moles
P1*V1 = P2*V2
P1*V1 = n1*R*T
P2*V2 = n2*R*T
(P1*V1)/R*T = (P2*V2)/n2*R*T
Since R and T do not change we can write as followed:
(P1*V1) = (P2*V2) /n2
n2 = (P2*V2) / (P1*V1)
n2 = (2.55 *1.25)/(0.75*3.75)
n2 = 1.13 moles
<u>Step 4:</u> Calculate mass of krypton gas
mass = Number of moles * Molar mass
mass of krypton gas = 1.13 moles * 83.798 g/mol = 94.69 grams ≈ 94.7 grams
There will be 94.7 grams of krypton gas
