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SashulF [63]
2 years ago
15

How many total moles of ions are released when each of the following dissolves in water?

Chemistry
1 answer:
Gnom [1K]2 years ago
5 0

Thus 3 moles of ions are released when samples dissolves definitely in water.

Water (H2O) is made from 2 atoms of hydrogen and 1 atom of oxygen. A mole of water molecules would be 2 moles of hydrogen atoms plus 1 mole of oxygen atoms.

<h3>How many ions are in a mole?</h3>

One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The variety 6.022 × 10²³ is acknowledged as Avogadro's number or Avogadro's constant.

<h3>How plenty is a mole of water?</h3>

18.0146 grams

The atomic mass of hydrogen is 1.0078 and the atomic mass of oxygen is 15.999, so the mass of a mole of water is two x 1.0078 + 15.999. Therefore, a mole of water, or 6.022 x 1023 molecules, weighs 18.0146 grams.

Learn more about moles of ion here:

<h3>brainly.com/question/15356425</h3><h3 /><h3>#SPJ4</h3>
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What is the end result <br> of diffusion?
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3 years ago
Convert 18.9 moles to MgCl2 to formula units
Masja [62]

Answer:

18.9 moles of MgCl2 = 17.834 kg of MgCl2

Explanation:

The molecular weight of MgCl is 80.0 g/mol . So, to convert the given mole amount to grams, multiply this by this number, which is constant for all compounds with a specific composition (mass fraction).

Considering the original question was in the context of chemistry, I wanted to make it seem formal and more educational too. Hopefully that worked!  

EDIT: Came up with some text around what happens inside cells that would have made it better if someone just had an issue converting units, but I doubt my answer will be accepted >.<

3 0
2 years ago
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO 3 ( s ) + 2
e-lub [12.9K]

<u>Answer:</u> The mass of calcium chloride formed is 15.21 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For calcium carbonate:</u>

Given mass of calcium carbonate = 32.0 g

Molar mass of calcium carbonate = 100 g/mol

Putting values in equation 1, we get:

\text{Moles of calcium carbonate}=\frac{32.0g}{100g/mol}=0.32mol

  • <u>For hydrochloric acid:</u>

Given mass of hydrochloric acid = 10.0 g

Molar mass of hydrochloric acid = 36.5 g/mol

Putting values in equation 1, we get:

\text{Moles of hydrochloric acid}=\frac{10.0g}{36.5g/mol}=0.274mol

The given chemical equation follows:

CaCO_3(s)+2HCl(aq.)\rightarrow CaCl_2(aq.)+H_2O(l)+CO_2(g)

By Stoichiometry of the reaction:

2 moles of hydrochloric acid reacts with 1 mole of calcium carbonate

So, 0.274 moles of hydrochloric acid will react with = \frac{1}{2}\times 0.274=0.137mol of calcium carbonate

As, given amount of calcium carbonate is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid produces 1 mole of calcium chloride.

So, 0.274 moles of hydrochloric acid will produce = \frac{1}{2}\times 0.274=0.137moles of calcium chloride.

Now, calculating the mass of calcium chloride from equation 1, we get:

Molar mass of calcium chloride = 111 g/mol

Moles of calcium chloride = 0.137 moles

Putting values in equation 1, we get:

0.137mol=\frac{\text{Mass of calcium chloride}}{111g/mol}\\\\\text{Mass of calcium chloride}=(0.137mol\times 111g/mol)=15.21g

Hence, the mass of calcium chloride formed is 15.21 grams.

4 0
3 years ago
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