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Evaluate the expression when a= 5 and x= -2 -a+6x Thankyou ! !

kirill [66]

The equation would be -5+(-12), so the answer would be -17 :)

5 0

2 years ago

Read 2 more answers

N+5n-3c PLS anyone I need this for my test And I need it right now pls

iVinArrow [24]

Answer:

I'm assuming this is a combining like terms question, in which case the answer would be 6n - 3c.

Step-by-step explanation:

I'm guessing your teacher wants you to combine the like terms, and 1n plus 5n = 6n, minus 3c is the answer, which is 6n - 3c. If your teacher wanted you to solve for each variable, you can't do that because you don't have enough information, and there's an infinite number of solutions.

Hope this helps! Feel free to give me Brainliest if you feel this helped. Have a good day, and good luck on your test. :)

7 0

2 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

a.

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

b.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

c.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

d.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

e.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

2 years ago

I’m Really lost if I could get a answer it would be greatly appreciated

Nataly [62]

<h3>Answers:</h3>

$f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}$

================================================

Work Shown:

Part 1

$f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\$

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

$g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\$

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out $\left(\sqrt{x-1}+5\right)^2$

6 0

2 years ago

Select all instances in which the variable described is binomial.

tino4ka555 [31]

Answer: a. , c. , d., e.

Step-by-step explanation:

A variable that counts how many times a certain event occurs in a particular number of trials is known as binomial random variable.

For each trial, there exist only two outcomes .

The probability of for each event is the same on each trial.

a. Event has two outcomes with same probability as 0.50, therefore the random variable represents the total number of flips required to get tails is a binomial random variable.

b. Total guidelines are 5.

Here total outcomes are not 2 , it does not meet with the conditions of binomial.

c. The random variable represents the total number of children from this pair of parents with blue eyes has two outcomes (where has or not.)

also, the probability of having blue eyes is same in each trial, so it represents binomial random variable.

d. The random variable represents the total number out of 567 customers with a checking account has two outcomes (checking or savings).

So, it represents binomial random variable.

e. The random variable represents the total number of ace cards observed has two outcomes ( ace or not ace).

So it represents the binomial random variable.

7 0

2 years ago