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3 years ago

Please help me with the question please ASAP I’ll mark u as a brnlist *2 questions

Mathematics

2 answers:

timurjin [86]3 years ago

5 0

Answer:

scale factor = $\frac{3}{2}$

Step-by-step explanation:

The scale factor is the ratio of corresponding sides, image to original, that is

scale factor = $\frac{WX}{AB}$ = $\frac{12}{8}$ = $\frac{3}{2}$

------------------------------------------

1 pizza costs $12.75 and feeds 4

To feed 24 students he needs 24 ÷ 4 = 6 pizzas , then

6 cost = 6 × $12.75 = $76.50

Kaylis [27]3 years ago

3 0

Answer:

First answer is 76.50 and the second one is scale factor of 1/2

Step-by-step explanation: Mark brainlist or im deleting my answer :)

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A man and a woman agree to meet at a cafe about noon. If the man arrives at a time uniformly distributed between 11:40 and 12:10

kompoz [17]

Answer:

0.3888

Step-by-step explanation:

To solve the exercise we need a neutral time, so we define at 12:00 as time 0.

If the man arrives in a uniformly distributed time between 11:40 and 12:10, the time is distributed from -20 to 10.

If the woman arrives in a time evenly distributed between 11:45 and 12:20, the time is distributed from -15 to 20.

Assuming that each one arrives at 12: X and 12: Y for men and women, then the space of our time is defined as

Man [-20,10]

Woman [-15,20]

So,

$f_x(x)=\frac{1}{10-(-20)}=\frac{1}{30}\\f_y(y)=\frac{1}{20-(-15)}=\frac{1}{35}$

Then,

$f_{xy}(x,y)=f_x(x)f_y(y)=\frac{1}{30} \frac{1}{35} = \frac{1}{1050}$

The probability of finding an arrival less than 5 minutes is

$P(|X-Y|\leq 5) = \int\limit^20_{-15} \int\limit^{x+5}_{x-5} f(x,y)dydx$

$P(|X-Y|\leq 5)= \frac{1}{1050}\int\limit^{20}_{-15} y|^{x+5}_{x-5}dx$

$P(|X-Y|\leq 5)= \frac{35*10}{900}=0.3888$

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3 years ago

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The equation of any circle is

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Therefore, our equation is as follows.

(x + 2)^2 + (y - 3)^2 = 16

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