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Pachacha [2.7K]
3 years ago
11

Find x (2x + 50) (3x - 10°) final answer needs to equal 90°!!!! Please help ??

Mathematics
1 answer:
bonufazy [111]3 years ago
6 0
Answer: x = 10°
(2x + 50) = 70°
(3x - 10) = 20°

Steps:
(2x + 50)° + (3x -10)° = 90°
2x + 50 + 3x - 10 = 90°
5x + 40 = 90°
5x = 50°
x = 10°

(2x + 50)
2(10) + 50
20 + 50
70

(3x - 10)
3(10) - 10
30 - 10
20

Check:
70 + 20 = 90
90 = 90 ✅
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Shelley is making a rectangular blanket with dimensions 8 1/2 feet by 5 1/2 feet. She purchases 10 yards of ribbon to put a bord
scoray [572]

Answer:

there are no options listed, but some statements that are true about this question are:

  • total perimeter = (8.5 x 2) + (5.5 x 2) = 28 feet = 9¹/₃ yards
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6 0
3 years ago
The weight of Jane and Jessica was in the ratio of 8 : 9. Jane gained 2 kg while Jessica lost 4 kg. They then had the same weigh
postnew [5]

Answer:

  48 kg

Step-by-step explanation:

The given relations can be used to write a system of equations for the two weights. Those can be solved to find Jane's weight.

__

<h3>setup</h3>

Let x and y represent Jane's and Jessica's original weight, respectively. The ratio of weights was ...

  x/y = 8/9

After the changes in weight, they were equal:

  x+2 = y-4

__

<h3>solution</h3>

Adding 4 to the second equation, we have an expression for y that can be substituted into the first equation.

  y = x +6 . . . . . . . . . . solve the second equation for y

  x/(x+6) = 8/9 . . . . . . substitute for y in the first equation

  9x = 8(x +6) . . . . . . . multiply by 9(x+6)

  x = 48 . . . . . . . . . . . simplify and subtract 8x

Jane weighed 48 kg at first.

_____

<em>Alternate solution</em>

The original difference in "ratio units" was 9-8 = 1 ratio unit. We find that this corresponds to 6 kg after the weight changes make the weights equal. Then 8 ratio units will be 8(6 kg) = 48 kg—Jane's original weight.

(This mental solution is virtually the same as the solution using equations shown above.)

3 0
2 years ago
The first term of a geometric sequence is 7, and the ratio (multiplier) is 3. what is the sum of the first 5 terms of the sequen
Anni [7]
Hello,

1)
a_{1}=7
a_{2}=7*3
a_{3}=7*3^2

a_{n}=7*3^{n-1}

s=a_{1}+a_{2}+a_{3}+a_{4}+a_{5}=7*(1+3^1+3^2+3^3+3^4)
=7*\frac{3^{5}-1}{3-1}
=7*242/2=847

2)
b_{8}=6*8^{8-1}=12582912




















4 0
3 years ago
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Answer: Your answers ×=5 !

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