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Fynjy0 [20]
3 years ago
6

Machinery purchased for $64,200 by Sheridan Co. in 2016 was originally estimated to have a life of 8 years with a salvage value

of $4,280 at the end of that time. Depreciation has been entered for 5 years on this basis. In 2021, it is determined that the total estimated life should be 10 years with a salvage value of $4,815 at the end of that time. Assume straight-line depreciation.
Required:
a. Prepare the entry to correct the prior year's depreciation, if necessary
b. Prepare the entry to record depreciation for 2015
Business
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

Sheridan Co.

a. It is not necessary to correct the prior year's depreciation.  Depreciation is an accounting estimate and does not require the adjustment of prior year's accounts when there is a correction in its estimates.

b. Entry to record depreciation for 2021:

Debit Depreciation Expense $4,387

Credit Accumulated Depreciation $4,387

To record the depreciation expense for the year.

Explanation:

a) Data and Calculations:

Purchase of machinery in 2016 = $64,200

Original estimated useful life = 8 years

Salvage value = $4,280

Depreciation amount = $59,920 ($64,200 - $4,280)

Depreciation expense per year = $7,490 ($59,920/8)

Accumulated depreciation for 5 years = $37,450

Net book value = $26,750 ($64,200 - $37,450)

Remaining estimated useful life = 5 years

Salvage value = $4,815

New depreciable amount = $21,935 ($26,750 - $4,815)

Depreciation expense per year = $4,387 ($21,935/5)

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Answer:

Monthly interest rate = 2.16666667%

Explanation:

Given:

Annual percentage rate = 26% = 26 / 100 = 0.26

Total number of months in a year = 12 month

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What is Cost Drivers ?

A cost driver causes a change in an activity's cost. The idea is most frequently applied to allocate overhead expenses to the quantity of produced units. In order to reduce the cost of overhead, it can also be utilized in activity-based costing analysis to identify the causes of overhead. An activity-based costing system may employ a variety of cost drivers. Just one cost driver should be employed if a company just cares about adhering to the minimum accounting standards to allocate overhead to produced items. Cost drivers include things like the amount of customer interactions, engineering change orders, machine hours consumed, and product returns, as well as the number of direct labor hours performed.

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1 year ago
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Both Bond Bill and Bond Ted have 10.4 percent coupons, make semiannual payments, and are priced at par value. Bond Bill has 5 ye
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Answer:

Ans,

a) If interest rates suddenly rise by 3 percent, Bill´s bond would drop by -20.02%  and Ted´s bond would go down by -36.07%

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b) If rates were to suddenly fall by 3 percent, Bill´s bond would rise by 26.79%

and Ted´s bond would rise too by 86.47%

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Explanation:

Hi, first let´s go ahead and establish the stable scenario, for that we are going to use the information of the problem but we need to add the discount rate of the bond or yield, which is the missing information. All this so this concept can be explained in a better way, so for this example we´ll say that the yield of both bonds is 10% compounded semi-annually, the same units as the coupon. Now we have to use the following formula.

Price=\frac{Coupon((1+Yield)^{n}-1) }{Yield(1+Yield)^{n} } +\frac{FaceValue}{(1+Yield)^{n} }

Where:

Coupon = (%Coupon/2)*FaceValue= (0.104/2)*1,000=52

Yield = we are going to assume 10% annual, that is 5% semi-annual

n = Payment periods (For Bill n=5*2=10, for Ted, n=22*2=44)

So, let´s see what is the price of each bond if the yield was 10% annual compounded semi-annually.

Price(Bill)=\frac{52((1+0.05)^{10}-1) }{0.05(1+0.05)^{10} } +\frac{1,000}{(1+0.05)^{10} } =1,015.44

In Ted´s case, that is:

Price(Ted)=\frac{52((1+0.05)^{44}-1) }{0.05(1+0.05)^{44} } +\frac{1,000}{(1+0.05)^{44} } = 1,035.33

Now, if the interest rate (Yield) suddenly goes up by 3%, this is what happens to Bill´s Bond

Price(Bill)=\frac{52((1+0.08)^{10}-1) }{0.08(1+0.08)^{10} } +\frac{1,000}{(1+0.08)^{10} } = 812.12

If yield goes down by 3%, this is the new price of Bill´s bond.

Price(Bill)=\frac{52((1+0.02)^{10}-1) }{0.02(1+0.02)^{10} } +\frac{1,000}{(1+0.02)^{10} } =  1,287.44

Now, in the case of Ted, this is what happens to the price if the yield goes up.

Price(Ted)=\frac{52((1+0.08)^{44}-1) }{0.08(1+0.08)^{44} } +\frac{1,000}{(1+0.08)^{44} } =  661.84

If it goes down by 3%, this would be the price for Ted´s bond.

Price(Ted)=\frac{52((1+0.02)^{44}-1) }{0.02(1+0.02)^{44} } +\frac{1,000}{(1+0.02)^{44} } =   1,930.56

Now, in percentage, what we need to use is the following formula.

Change=\frac{(VariationValue-BaseValue)}{BaseValue} x100

For example, in the case of Bill´s bond, which yield went up by 3%, this is what we should do.

Change=\frac{(812.12-1,015.44)}{1,015.44} x100=-20.02Percent

So, the price variation is -20.02% if the yield rises by 3%.

This are the results of the prices and calculations for you to answer this question. Best of luck.

                         Bill        Ted                       % (Bill)       %(Ted)

Base Price     $1,015.44    $1,035.33    

(+) 3% Yield  $812.12          $661.84      -20.02%          -36.07%

(-) 3% Yield  $1,287.44     $1,930.56       26.79%            86.47%

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