Answer:
II. One and only one solution
Step-by-step explanation:
Determine all possibilities for the solution set of a system of 2 equations in 2 unknowns. I. No solutions whatsoever. II. One and only one solution. III. Many solutions.
Let assume the equation is given as;
x + 3y = 11 .... 1
x - y = -1 ....2
Using elimination method
Subtract equation 1 from 2
(x-x) + 3y-y = 11-(-1)
0+2y = 11+1
2y = 12
y = 12/2
y = 6
Substitute y = 6 into equation 2:
x-y = -1
x - 6 = -1
x = -1 + 6
x = 5
Hence the solution (x, y) is (5, 6)
<em>Hence we can say the equation has One and only one solution since we have just a value for x and y</em>
<em />
D 28 miles you want to multiply by 4 so 7x4 =28
24,717.
What you have to do is subtract 38,773-14,056 and then the answer would be 24,717. So all together 24,717 must be added to result in the sum of 38,773.
14,056+24,717=38,773.
Answer:
x= 3 +
, 3 -
Step-by-step explanation:
You use the quadratic formula to get x= 
Then you simplify and get the answers x= 3 +, 3 -
