The answer should be C. 3
A. <span>isolating the x² term and finding the square root of both sides </span>
Answer:
A=(16 -5 0 -9)-(3 -4 -11 24)
Step-by-step explanation:
The solution process for any algebraic expression is to "undo" what is done to the variable. Here, matrix A has (3 -4 -11 24) added to it. The next step is to undo that addition, by subtracting that amount from both sides of the equation. The result is ...
A = (16 -5 0 -9)-(3 -4 -11 24)
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We assume there are typos in the answer choices listed here.
Answer:
B. (1,5) and (5.25, 3.94)
Step-by-step explanation:
The answer is where the 2 equations intersect.
We need to solve the following system of equations:
y = -x^2 + 6x
4y = 21 - x
From the second equation:
x = 21 - 4y
Plug this into the first equation:
y = -(21 - 4y)^2 + 6(21 - 4y)
y = -(441 - 168y + 16y^2)+ 126 - 24y
y = -441 + 168y - 16y^2 + 126 - 24y
16y^2 + y - 168y + 24y + 441 - 126 = 0
16y^2 - 143y + 315 = 0
y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)
y = 5, 3.938
When y = 5:
x = 21 - 4(5) = 1
When y = 3.938
x = 21 - 4(3.938) = 5.25.