Question

a crowbar having the lenght of 1.75 is used to balance a load of 500N if the distance between the fulcrum and the load is 0.5m find the effort applied to balance the load​

Answer 1

The effort applied = 200 N

Further explanation

Equilibrium :

$\tt F_1.d_1=F_2.d_2$

Total length = 1.75

The distance between the fulcrum and the load is 0.5 m ⇒ d₁=0.5 m

The distance between the fulcrum and the force applied :

$\tt 1.75-0.5=1.25~m\rightarrow d_2=1.25~m$

A load of 500N ⇒ F₁=500 N

The force applied :

$\tt 500\times 0.5=F_2\times 1.25\\\\F_2=\dfrac{500\times 0.5}{1.25}=200~N$