Question

A glass flask whose volume is 1000 cm3 at a temperature of 1.00 ∘C is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52.0 ∘C , a volume of 8.25 cm3 of mercury overflows the flask.If the coefficient of volume expansion of mercury is 18.0×10−5K−118.0×10 compute the coefficient of volume expansion of the glass.

Answer 1

Answer:

$1.8\times 10^{-5}/K$

Explanation:

Volume of glass flask,$V_0=1000 cm^3$

$T_1=1.00^{\circ} C$

$T_2=52.0^{\circ} C$

Over flow$\Delta V=8.25 cm^3$

Coefficient of mercury=$\beta_{Hg}=18.0\times 10^{-5}/K$

$\Delta V_{Hg}=\beta_{Hg}V_0(T_2-T_1)=18\times 10^{-5}\times 1000\times (52-1)$

$\Delta V_{Hg}=9.18 cm^3$

$\Delta_{gass}=\Delta V-\Delta_{Hg}=9.18-8.25=0.93 cm^3$

$\beta_{gass}=\frac{\Delta V_{gass}}{V_0(T_2-T_1)}$

$\beta_{gass}=\frac{0.93}{1000\times (52-1)}$

$\beta_{gass}=1.8\times 10^{-5}/K$

Hence, the coefficient of volume expansion of the glass=$1.8\times 10^{-5}/^{\circ} C$