Answer: True
Explanation: Because of the way this water cycle has always circulated our planet, there is indeed a chance that the water in your glass is the same water that thirsty dinosaurs were drinking about 65 million years ago
Answer:
A flame always point upwards because the flame's gas is hotter than the surrounding air and, like you said, a hot gas is always lighter or less dense than a cold gas.
Explanation:
Answer:
From the previous explanation Student No. 1 has the correct explanation
Explanation:
When the fluorescent lamp emits a light it has the shape of its emission spectrum, this light collides with the atoms of Nitrogen and excites it, so these wavelengths disappear, lacking in the spectrum seen by the observed, for which we would see an absorption spectrum
The nitrogen that was exited after a short time is given away in its emission lines, in general there are many lines, so the excitation energy is divided between the different emission lines, which must be weak
From the previous explanation Student No. 1 has the correct explanation
Answer:
Part a)
![T = 2\sqrt{\frac{R}{3g}}](https://tex.z-dn.net/?f=T%20%3D%202%5Csqrt%7B%5Cfrac%7BR%7D%7B3g%7D%7D)
Part b)
![v_x = \frac{\sqrt{3Rg}}{2}](https://tex.z-dn.net/?f=v_x%20%3D%20%5Cfrac%7B%5Csqrt%7B3Rg%7D%7D%7B2%7D)
Part c)
![v_y = \sqrt{Rg/3}](https://tex.z-dn.net/?f=v_y%20%3D%20%5Csqrt%7BRg%2F3%7D)
Part d)
![v = \frac{1}{2}\sqrt{13Rg}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Csqrt%7B13Rg%7D)
Part e)
![\theta_i = 33.7 degree](https://tex.z-dn.net/?f=%5Ctheta_i%20%3D%2033.7%20degree)
Part f)
![H = \frac{13R}{8}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B13R%7D%7B8%7D)
Part g)
![X = \frac{13R}{4}](https://tex.z-dn.net/?f=X%20%3D%20%5Cfrac%7B13R%7D%7B4%7D)
Explanation:
Initial speed of the launch is given as
initial speed = ![v_i](https://tex.z-dn.net/?f=v_i%20)
angle =
degree
Now the two components of the velocity
![v_x = v_i cos\theta_i](https://tex.z-dn.net/?f=v_x%20%3D%20v_i%20cos%5Ctheta_i)
similarly we have
![v_y = v_i sin\theta_i](https://tex.z-dn.net/?f=v_y%20%3D%20v_i%20sin%5Ctheta_i)
Part a)
Now we know that horizontal range is given as
![R = \frac{v_i^2 (2sin\theta_icos\theta_i)}{g}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7Bv_i%5E2%20%282sin%5Ctheta_icos%5Ctheta_i%29%7D%7Bg%7D)
maximum height is given as
![H = \frac{R}{6} = \frac{v_i^2 sin^2\theta_i}{2g}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7BR%7D%7B6%7D%20%3D%20%5Cfrac%7Bv_i%5E2%20sin%5E2%5Ctheta_i%7D%7B2g%7D)
so we have
![v_i sin\theta = \sqrt{Rg/3}](https://tex.z-dn.net/?f=v_i%20sin%5Ctheta%20%3D%20%5Csqrt%7BRg%2F3%7D)
time of flight is given as
![T = \frac{2v_isin\theta_i}{g}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2v_isin%5Ctheta_i%7D%7Bg%7D)
![T = \frac{2\sqrt{Rg/3}}{g}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Csqrt%7BRg%2F3%7D%7D%7Bg%7D)
![T = 2\sqrt{\frac{R}{3g}}](https://tex.z-dn.net/?f=T%20%3D%202%5Csqrt%7B%5Cfrac%7BR%7D%7B3g%7D%7D)
Part b)
Now the speed of the ball in x direction is always constant
so at the peak of its path the speed of the ball is given as
![R = v_x T](https://tex.z-dn.net/?f=R%20%3D%20v_x%20T)
![R = v_x 2\sqrt{\frac{R}{3g}}](https://tex.z-dn.net/?f=R%20%3D%20v_x%202%5Csqrt%7B%5Cfrac%7BR%7D%7B3g%7D%7D)
![v_x = \frac{\sqrt{3Rg}}{2}](https://tex.z-dn.net/?f=v_x%20%3D%20%5Cfrac%7B%5Csqrt%7B3Rg%7D%7D%7B2%7D)
Part c)
Initial vertical velocity is given as
![v_y = v_i sin\theta_i](https://tex.z-dn.net/?f=v_y%20%3D%20v_i%20sin%5Ctheta_i)
![v_i sin\theta = \sqrt{Rg/3}](https://tex.z-dn.net/?f=v_i%20sin%5Ctheta%20%3D%20%5Csqrt%7BRg%2F3%7D)
Part d)
Initial speed is given as
![v = \sqrt{v_x^2 + v_y^2}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Bv_x%5E2%20%2B%20v_y%5E2%7D)
so we will have
![v = \sqrt{Rg/3 + 3Rg/4}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7BRg%2F3%20%2B%203Rg%2F4%7D)
![v = \frac{1}{2}\sqrt{13Rg}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Csqrt%7B13Rg%7D)
Part e)
Angle of projection is given as
![tan\theta_i = \frac{v_y}{v_x}](https://tex.z-dn.net/?f=tan%5Ctheta_i%20%3D%20%5Cfrac%7Bv_y%7D%7Bv_x%7D)
![tan\theta_i = \frac{\sqrt{Rg/3}}{\sqrt{3Rg}/2}](https://tex.z-dn.net/?f=tan%5Ctheta_i%20%3D%20%5Cfrac%7B%5Csqrt%7BRg%2F3%7D%7D%7B%5Csqrt%7B3Rg%7D%2F2%7D)
![\theta_i = 33.7 degree](https://tex.z-dn.net/?f=%5Ctheta_i%20%3D%2033.7%20degree)
Part f)
If we throw at same speed so that it reach maximum height
then the height will be given as
![H = \frac{v^2}{2g}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7Bv%5E2%7D%7B2g%7D)
![H = \frac{13R}{8}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B13R%7D%7B8%7D)
Part g)
For maximum range the angle should be 45 degree
so maximum range is
![X = \frac{v^2}{g}](https://tex.z-dn.net/?f=X%20%3D%20%5Cfrac%7Bv%5E2%7D%7Bg%7D)
![X = \frac{13R}{4}](https://tex.z-dn.net/?f=X%20%3D%20%5Cfrac%7B13R%7D%7B4%7D)
<span>Mercury, Venus, Earth, and Mars are all ___inner___ planets. This is because they are all within the asteroid belt.</span>