Answer:
To find the mass using density and volume we just multiply them against each other which causes ml to cancel and just leaves us with grams which represents how much the item weights.
Therefore, our final answer is that our pencil weight 3.5 grams
<u><em>Hope this helps! Let me know if you have any questions</em></u>
-- There are 80 protons in the nucleus of every atom of Mercury,
but only 8 of them in the nucleus of an atom of Oxygen.
-- Mercury must be warmer than 357°C in order to boil, but Oxygen
must only be warmer than -183°C.
-- Mercury must be colder than -39°C in order to freeze, but Oxygen
must be colder than -219°C.
-- Oxygen is required for human life. Mercury is a deadly poison.
Answer:
For every action, there is an equal and opposite reaction.
Explanation:
Let's say I threw a ball on the wall. The image shows the instance the ball comes into contact with the wall.
If you would look at the image above,
- F1 and F2 are acting in opposite directions.
- They both have the same magnitude too.
F1 is the force of the ball on the wall (action force) and F2 is the force of the wall on the ball (reaction force). This is called an action-reaction pair.
The answer is 3 m. This is the area under the graph from t=2 to t=3, using the trapezium rule. 1/2 (2+4) * 1
Answer:
xcritical = d− m1
/m2
( L
/2−d)
Explanation: the precursor to this question will had been this
the precursor to the question can be found online.
ff the mass of the block is too large and the block is too close to the left end of the bar (near string B) then the horizontal bar may become unstable (i.e., the bar may no longer remain horizontal). What is the smallest possible value of x such that the bar remains stable (call it xcritical)
. from the principle of moments which states that sum of clockwise moments must be equal to the sum of anticlockwise moments. aslo sum of upward forces is equal to sum of downward forces
smallest possible value of x such that the bar remains stable (call it xcritical)
∑τA = 0 = m2g(d− xcritical)− m1g( −d)
xcritical = d− m1
/m2
( L
/2−d)
