Question

The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 72 cm, what is the

Answer 1

Answer:

Step-by-step explanation:

W=2L-2

A=72

LW=72

L(2L-2) = 72

2L^2 -2L= 72

2L^2 -2L-72=0

L^2 - L -36 = 0

L= -5.52 or 6.52(neg # not a solution)

W=11.04

L=6.52

DIAG = $\sqrt{11.04^2+6.52^2}$ = 12.82

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