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lesya [120]
4 years ago
9

There are 79 milligrams of cholesterol in a 3.3​-ounce serving of lobster. How much cholesterol is in 8 ounces of​ lobster?

Mathematics
2 answers:
Ne4ueva [31]4 years ago
8 0

Answer: 191.5 milligrams

Step-by-step explanation: first find how many milligrams is in 1 ounce. That is 23.9. Now 8 x 23.9 is 191.5 milligrams of cholesterol.

skelet666 [1.2K]4 years ago
8 0

Answer:

79/3.3=23.939= the amount of milligrams in 1 ounce

therefore, 23.939*8=191.512

therefore, there are 191.512 milligrams of cholesterol in 8 ounces of lobster

Step-by-step explanation:

i think thats answer, idk how to explain

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The clock was exactly on time at 7am at 1pm the clock was 228 seconds late at that rate how slow was the clock half an hour
yan [13]

Answer:

19 seconds.

Step-by-step explanation:

Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:

1 PM = 13:00

13 - 7 = 6

228/6 = 38

38/2 = 19

Thus, every half hour the clock is delayed 19 seconds.

4 0
3 years ago
Write the product in simplest form: -8w * (-w)
Hitman42 [59]
8w

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7 0
3 years ago
How many nonzero terms of the Maclaurin series for ln(1 x) do you need to use to estimate ln(1.4) to within 0.001?
Vilka [71]

Answer:

The estimate of In(1.4) is the first five non-zero terms.

Step-by-step explanation:

From the given information:

We are to find the estimate of In(1 . 4) within 0.001 by applying the function of the Maclaurin series for f(x) = In (1 + x)

So, by the application of Maclurin Series which can be expressed as:

f(x) = f(0) + \dfrac{xf'(0)}{1!}+ \dfrac{x^2 f"(0)}{2!}+ \dfrac{x^3f'(0)}{3!}+...  \ \ \  \ \ --- (1)

Let examine f(x) = In(1+x), then find its derivatives;

f(x) = In(1+x)          

f'(x) = \dfrac{1}{1+x}

f'(0)   = \dfrac{1}{1+0}=1

f ' ' (x)    = \dfrac{1}{(1+x)^2}

f ' ' (x)   = \dfrac{1}{(1+0)^2}=-1

f '  ' '(x)   = \dfrac{2}{(1+x)^3}

f '  ' '(x)    = \dfrac{2}{(1+0)^3} = 2

f ' '  ' '(x)    = \dfrac{6}{(1+x)^4}

f ' '  ' '(x)   = \dfrac{6}{(1+0)^4}=-6

f ' ' ' ' ' (x)    = \dfrac{24}{(1+x)^5} = 24

f ' ' ' ' ' (x)    = \dfrac{24}{(1+0)^5} = 24

Now, the next process is to substitute the above values back into equation (1)

f(x) = f(0) + \dfrac{xf'(0)}{1!}+ \dfrac{x^2f' \  '(0)}{2!}+\dfrac{x^3f \ '\ '\ '(0)}{3!}+\dfrac{x^4f '\ '\ ' \ ' \(0)}{4!}+\dfrac{x^5f' \ ' \ ' \ ' \ '0)}{5!}+ ...

In(1+x) = o + \dfrac{x(1)}{1!}+ \dfrac{x^2(-1)}{2!}+ \dfrac{x^3(2)}{3!}+ \dfrac{x^4(-6)}{4!}+ \dfrac{x^5(24)}{5!}+ ...

In (1+x) = x - \dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\dfrac{x^5}{5}- \dfrac{x^6}{6}+...

To estimate the value of In(1.4), let's replace x with 0.4

In (1+x) = x - \dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\dfrac{x^5}{5}- \dfrac{x^6}{6}+...

In (1+0.4) = 0.4 - \dfrac{0.4^2}{2}+\dfrac{0.4^3}{3}-\dfrac{0.4^4}{4}+\dfrac{0.4^5}{5}- \dfrac{0.4^6}{6}+...

Therefore, from the above calculations, we will realize that the value of \dfrac{0.4^5}{5}= 0.002048 as well as \dfrac{0.4^6}{6}= 0.00068267 which are less than 0.001

Hence, the estimate of In(1.4) to the term is \dfrac{0.4^5}{5} is said to be enough to justify our claim.

∴

The estimate of In(1.4) is the first five non-zero terms.

8 0
3 years ago
The lemonade cooler at the class picnic holds 12.5L. One liter is approximately equal to 0.26 gallons. How many gallons does the
lora16 [44]

Answer: There are 3.25 or 3 1/4 gallons in one cooler

Step-by-step explanation:

If one liter is appx .26 gallons we need to multiply the number of liters there are. So 12.5 times .26 to get the answer 3.25

4 0
3 years ago
Consider the following sets.
Andrews [41]
A = {x ≥ 3}, B = {x ≤ 1}

So A∪B = {x ≥ 3 or x ≤ 1}

So for x ⊆(1,3), A∪B = ∅

Apparently, (1,3) covers the first option, a will be the answer
6 0
3 years ago
Read 2 more answers
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