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Tems11 [23]
3 years ago
5

How can we relate density and pressure in liquids ??

Physics
2 answers:
Masteriza [31]3 years ago
6 0
Pressure increases with increasing depth. h2=2hh
Otrada [13]3 years ago
5 0

<u>How can we relate density and pressure in liquids ??</u>

\huge{ \texttt{ \red{answers}}}

  • It is the pressure at each point of a static fluid. When we immerse ourselves in a liquid, the pressure increases with depth.
  • In the case of a liquid (constant density) the pressure increases linearly with depth.

⭐ ----------------------------------------------------------------------------------⭐

\bold{BRAINLY MENTALMENTE}

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A Young'sdouble-slit interference experiment is performed with monochromatic light. The separation between the slits is 0.44 mm.
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Answer:

Explanation:

The double slit interference phonemene is described for the case of constructive interference

          d sin θ= m λ                   (1)

let's use trigonometry to find the sinus

        tan θ = y / L

in general in interference phenomena the angles are small

       tan θ = sin θ / cos θ = sin θ

 

The double slit interference phonemene is described for the case of constructive interference

          d sin θ = m lam                    (1)

let's use trigonometry to find the sinus

        tan θ = y / L

in general in interference phenomena the angles are small

       tan θ = sin θ / cos θ = sin θ

we substitute

      sin θ = y / L

we substitute in equation 1

         d y / L = m λ

         λ = dy / L m

let's reduce the magnitudes to the SI system

  d = 0.44 mm = 0.44 10⁻³ m

  y = 5.5 mm = 5.5 10⁻³ m

  L = 4.2m

  m = 1

let's calculate

        λ = 0.44  10⁻³ 5.5 10⁻³ / (4.2 1)

         

        λ = 5.76190 10-7 m

let's reduce to num

  lam = 5.56190 10-7 m (109 nm / 1m)

  lam = 556,190 nmtea

we substitute

      without tea = y / L

we substitute in equation 1

         d y / L = m lam

         lam = dy / L m

let's reduce the magnitudes to the SI system

  d = 0.44 me = 0.44 10-3 m

  y = 5.5 mm = 5.5 10-3

  L = 4.2m

  m = 1

let's calculate

        lam = 0.44 10⁻³  5.5 10⁻³ / (4.2 1)

         

        lam = 5.76190 10⁻⁷ m

let's reduce to num

  lam = 5.56190 10⁻⁷ m (109 nm / 1m)

  lam = 556,190 nm

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