Answer:height above ground at which projectile have velocity
0.5v is (0.0375v^2)
Explanation:
Using Vf = Vi - gt
Where Vf is final velocity
Vi is initial velocity
g is the acceleration due to gravity
t is the time taken
So, 0.5v = v - gt
t = 0.05v
Therefore height h = vt - 0.5gt^2
Subtitute t
h = 0.05v^2 - 0.0125v^2
h = 0.0375v^2
Answer: F = 2917.2N
Explanation: To solve the question, we will employ Newton 2nd law of motion.
After hitting, the ball stop and no rebound.
The force exert by the ball is equal to the average force the fist will exert on the head.
Please find the attached file for the solution
I think the force of spinning it can only hold for so long and because of gravitys pressure.(i hope i helped) :)
Answer: I do not mind if I have more rewards or not.
Explanation: I think helping others is the best reward
Answer:
mass
Explanation:
astronomers use Newtons gravitational law as a link between gravity and orbits to measure the masses of stars and planets.
Newtons gravitational law states that the gravitational force of attraction between two planets is proportional to their masses and inversely proportional to the square of the distance between them.