Answer:
<em>The horizontal velocity vector of the canonball does not change at all, but is constant throughout the flight.</em>
Explanation:
First, I'll assume this is a projectile simulation, since no simulation is shown here. That been the case, in a projectile flight, there is only a vertical component force (gravity) acting on the body, and no horizontal component force on the body. The effect of this on the canonball is that the vertical velocity component on the canonball goes from maximum to zero at a deceleration of 9.81 m/s^2, in the first half of the flight. And then zero to maximum at an acceleration of 9.81 m/s^2 for the second half of the flight before hitting the ground. <em>Since there is no force acting on the horizontal velocity vector of the canonball, there will be no acceleration or deceleration of the horizontal velocity component of the canonball. This means that the horizontal velocity component of the canonball is constant throughout the flight</em>
A falling raindrop.
The reason why it's because mass of a raindrop is under influence of gravity pushing it down towards earth surface. When it hit the surface kinetic energy is released.
It represents where it is located in the periodic table and how many protons a element has.
Answer:

Explanation:
From the question we are told that:
Mass of pulley 
Radius 
Mass of block A 
Mass of block B 
Spring constant
Generally the equation for Torque is mathematically given by
Since 
At mass A

At mass B

At Pulley


Therefore the equation for total force F
At mass A+At mass B+At Pulley




Since From above equation

Therefore



Generally the equation for frequency is mathematically given by

