Answer:
What equation? Here’s a big tip for you, equations contain an ‘equals sign’ (‘=’) and something that they are equal to. I’m assuming your equation is:
ax2+bx+c=0
I’m going to use p and q for the roots of the equation as they are easier to type than α and β . Thus we have:
a(x−p)(z−q)=0⇒ax2−a(p+q)x+apq=0
Equating coefficients with our initial equation:
x1 : b=−a(p+q)⇒p+q=−ba
x0 : c=apq⇒pq=ca
Now p2+q2=p2+2pq+q2−2pq=(p+q)2−2pq
=(−ba)2−2ca
=b2a2−2ca
=b2−2aca2
Answer:
is it a random answer or are there options?
Step-by-step explanation:
Alright, so by finding a common denominator (with a bit of guess and check) we get 1/16=5/80 (since 80/16=5 and 5*1=5), 7/10=56/80, and 5/8=50/80.
In addition, 6/5=96/80. To get this, we'd want 6 as the numerator and 5 as the denominator. Noting that we have parenthesis (meaning that (7/10 has to start with the parenthesis and 5/8) has to end it), we can also notice that (56-50)/80=6/80 and since 1/16=5/80, we can divide them to get (6/80)/(5/80)=
(6*80)/(5*80)=6/5
Answer:
5x^2 -22x +8 -32/(x+2)
Step-by-step explanation:
See the attachment for the work. The root being evaluated is -2. Each value on the second row is -2 times the previous third row value. The third row value is the sum of the first two rows.
The final lower-right number is the "remainder." By the remainder theorem, it is also the value of the polynomial at x=-2.
Answer:
no question
Step-by-step explanation:
