Active and passive humoral immunity are both mechanisms of adaptive immunity that use antibodies. yes this is true
- Our adaptive immune system protects us from infection-related mortality. An new-born born with a significantly compromised adaptive immune system may die shortly unless extreme steps are taken to isolate it from a wide range of infectious agents such as bacteria, viruses, fungi, and parasites.
- The purpose of adaptive immunity is to eliminate invading infections as well as any harmful chemicals they create. Because these reactions are damaging, it is critical that they only occur in response to molecules that are alien to the host and not to molecules that are native to the host. The adaptive immune system's capacity to identify what is foreign from what is self is a fundamental feature.
To learn more about adaptive immune.
brainly.com/question/17094294
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The answer would be A and E
(I explained on the other one)
Answer:
O happiness
Explanation:
According to this question, Dopamine is a neurotransmitter that makes a person feel happy when released in the brain. However, it is stated that certain drugs stop the synapses from removing neurotransmitters, like Dopamine.
Hence, when these drugs cause the amount of neurotransmitters in the synapses to be increased, this means that the response caused by those neurotransmitters will also be increased. For example, an increase in Dopamine will cause an increase in HAPPINESS.
A population of frogs with
slightly different coloring is an example of microevolution. Microevolution is
the changes in the gene pool of a population that can be measured and observed in
short periods of time within a population. Microevolution can take place in
several ways such as gene flow, genetic drift, mutation and selection.
Answer:
Null Hypothesis -
The observed frequency is approximately equal to the expected frequency of phenotype.
Explanation:
Pure Breeding Cross - TTww x ttWW
Genotype of offspring in F2 generation - TtWw
Null Hypothesis -
The observed frequency is approximately equal to the expected frequency of phenotype.
The chi square analysis is attached
The degree of freedom for this question is 3
The p value for X^2 estimated through chi square test is 0.5
Hence the null hypothesis is accepted.
