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Dmitriy789 [7]
3 years ago
14

Suppose that your boss must choose four employees in your office to attend a conference in Jamaica. Because all 15 of you want t

o go, he decides that the only fair way is to draw names out of a hat. What is the probability that you, Kyle, Carol, and Adam are chosen? Enter a fraction or round your answer to 4 decimal places, if necessary.
Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer:

1 / 1365

Step-by-step explanation:

Given that :

Number of employees to choose from = 15

Number of employees to be chosen = 4

Probability of choosing You, Kyle, Carol and Adam

Recall ;

P(A) = number of required outcome / Total possible outcomes

Number of required outcome = 4C4

Total possible outcomes = 15C4

nCr = n! ÷ (n-r)!r!

Using calculator to save computation time :

15C4 = 1365

4C4 = 1

P(choosing you, Kyle, Carol and Adam) :

1 / 1365

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Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

draw \: CE \: \parallel \: AD \:  \\ and \: CD \: \perp \: AE

Now , we can clearly see that AECD is a parallelogram !

\therefore AE = CD = 13 cm

Now ,

AB = AE + BE \\\implies \: BE =AB -  AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm

Now , In ∆ BCE ,

semi \: perimeter \: (s) =  \frac{15 + 15 + 12}{2}  \\  \\ \implies \: s =  \frac{42}{2}  = 21 \: cm

Now , by Heron's formula

area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

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Answer:

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+

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X^2-7x+6-x - 6

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X/x-1 / 2x/x+4

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X^2+1 + x-4

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X^2+1 - x-4

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(-k^2+1) (-k-4)

K^3+4k^2-k-4

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K-2^2+1 / k-2 -2

= K^2-4k+5 / k-4

Step-by-step explanation:

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Let,

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Price of one adult ticket is $9 and price of one student ticket is also $9.

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Learn more about linear equations at:

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