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gavmur [86]
3 years ago
10

Eight years ago, the daughters age was thrice the son's age. Now the daughter's age is 4 years more than the son's age. Find the

ir present ages.​
Mathematics
1 answer:
vekshin13 years ago
5 0

Answer:

Let s be the son’s current age and d be the daughter’s current age. The system of equations is:

s - 10 = 2(d - 10)

s = 3 + d

Since s is already set to an equation, we can use the substitution method for s in the other equation:

s = 3 + d

s - 10 = 2(d - 10)

3 + d - 10 = 2(d - 10)

Simplify and solve for d:

3 + d - 10 = 2(d - 10)

-7 + d = 2d - 20

-7 = d - 20

13 = d

The daughter is 13 years old. To solve for the son’s age, we will plug in the solution for d into one of the equations. The second one is simpler so we will use that:

s = 3 + d

s = 3 + 13

s = 16

The son is 16 years old. Let us use the other equation to check our solutions:

s - 10 = 2(d - 10)

16 - 10 = 2(13 - 10)

6 = 2(3)

6 = 6

It checks out. The son is 16 years old, and the daughter is 13 years old.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

To Find:

Value of expression

75 ÷ 5 - [( 9 - 7 ) × 3 ] × 2

Solution:

PEDMAS rule

It explains the order of operations to solve an expression.

According to Pedmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.),

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E- exponent

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A/S - Add or Sub which ever comes first.

So first we will solve the Parenthesis we get

Step 1. Parenthesis  operation

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Step 2. Parenthesis operation

75\div 5 - [(2)\times 3 ]\times 2

Step 3. Division

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Step 4. Multiplication

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