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FrozenT [24]
3 years ago
14

Suppose a culture containing 2*108 bacteria was exposed to ionizing radiation sufficient to kill 99.99% of the cells. calculate

the number of bacteria you expect to survive this treatment.
Biology
1 answer:
Kaylis [27]3 years ago
7 0
<span>The culture contains 2*10^8 bacteria before it was exposed to ionizing radiation which kills 99.99% of the bacteria. The number of bacteria left after the radiation would be:

final number= initial number * (100%- radiation kill rate)
</span>final number= 2*10^8<span>  *(100%-99.99%)
</span>final number= 2*10^8  *(0.01%)
final number= 2*10^8  * 10^-6
final number= 2*10^(8-6)
final number= 2*10^2
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