All categories

3 years ago

Which statement is true?

Mathematics

1 answer:

Anna007 [38]3 years ago

4 0

The value of money remains constant over time

You might be interested in

Kyle drew 4 polygons labeled A,B,C, and D. Figure A has twice as many sides as Figure B. Figure B has 3 vertices. Figure C has h

erma4kov [3.2K]

Answer:

Figure A - hexagon

Figure B - triangle

Figure C - rectangle

Figure D - octagon

Step-by-step explanation:

If figure B has 3 vertices (angles), then that means it is a triangle (3 sides)

So that means figure A has 6 sides, (hexagon)

And figure D has 8 vertices, so 8 sides (octagon)

And if C has half as many, that would be 4 (rectangle)

7 0

4 years ago

Do you notice clusters or outliners in the data ? Explain your reasoning

Kay [80]

Yes,I do 1,110 is a cluster because it’s a very large number for 52 degrees and 189 is because it’s a very large number for 16 degrees.

Hope this helps :)

4 0

3 years ago

27bc/36cd<br><br> simplify.<br><br> i will mark brainliest

AlekseyPX

Both the numerator and denominator have a 9 and a "b" in common, so we can reduce the fraction to:

3c/4d

5 0

3 years ago

A real estate agent has 8 master keys to open several new homes. Only 1 master key will open any given house. If 40% of these ho

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

Suppose F represents the value that a room is unlocked.

Then, we can assume that the probability of unlocked homes is:

P(unlocked homes) = P(U)

P(unlocked homes) = 40%

P(unlocked homes) = 0.40

Also, let us represent the value of the locked room with G.

P(locked homes) = P(G)

P(locked homes) = (1 - 0.40)

P(locked homes) = 0.60

Let the probability of selecting a correct key be P(S)

It implies that for the agent to use 3 keys, we have a combination of $^8C_3$ possible ways for the set of keys.

Now; since only one will open the house, then:

P(select correct key) = P(S)

$P(S) = \dfrac{ (^1_1) (^7_2) }{ ^8_3 }$

$P(S) = \dfrac{21}{56}$

P(S) = 0.375

Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:

P(F ∪ (G∩S) = P(F) + P(G∩S)

P(F ∪ (G∩S) = P(F) + P(G) × P(S)

P(F ∪ (G∩S) = 0.40 + (0.60×0.375)

P(F ∪ (G∩S) = 0.40 + 0.225

P(F ∪ (G∩S) =0.625

5 0

3 years ago

Give an example of a quadratic function that has no real root but has 2 complex solutions.

Nimfa-mama [501]

Step-by-step explanation:

An example : x² + 1 = 0....

7 0

3 years ago