Why does a person need food?

Chemistry

2 answers:

USPshnik [31]2 years ago

3 0

So they won’t die !!! People need food to live, food gives people energy and strength

jok3333 [9.3K]2 years ago

3 0

Answer:

because their body needs to have something in order to function.

Explanation:

You might be interested in

2. A submarine is able to raise and lower itself

Ronch [10]

Answer:

I think it's the state of the surrounding water because if the water holds impurities it will float and if it doesn't have impurities it will sink

4 0

3 years ago

Ionic bonds •ionic bonds form between ______________ and _________________. •in naming simple ionic compounds, the ____________

grigory [225]

Metals, non-metals
metal, non-metal
water
ionise
salts
low

6 0

3 years ago

What mass of carbon dioxide is produced upon complete combustion

SOVA2 [1]

Answer:

1 mole CO2 = 44g i.e.by the complete combustion of 12g of carbon, 44g of CO2 is produced.

Explanation:

8 0

2 years ago

Read 2 more answers

Hydrazine (N2H4) is a fuel used by some spacecraft. It is normally oxidized by N2O4 according to the following equation: N2H4(l)

vitfil [10]

Answer:

The enthalpy of the reaction is coming out to be -380.16 kJ.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$N_2H_4(l)+N_2O_4(g)\rightarrow 2N_2O(g)+2H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2 mol\times \Delta H_f_{(N_2O)})+(2 mol\times\Delta H_f_{(H_2O)} )]-[(1 mol\times \Delta H_f_{(N_2H_4)})+(1 mol\times \Delta H_f_{(N_2O_4)})]$

We are given:

$\Delta H_f_{(N_2O)}=81.6 kJ/mol\\\Delta H_f_{(H_2O)}=-241.8 kJ/mol\\\Delta H_f_{(N_2H_4)}= 50.6 kJ/mol\\\Delta H_f_{(N_2O_4)}=9.16 kJ/mo$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(2 mol\times 81.6 kJ/mol)+2 mol\times -241.8 kJ/mol)]-[(1 mol\times (50.6 kJ/mol))+(1 mol\times (9.16))]\\\\\Delta H_{rxn}=-380.16 kJ$