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fiasKO [112]
2 years ago
10

a vehicle accelerates with 0.4 m/s. calculate tue time taken by the vehicle to increase its speed from 20m/s to 40m/s.​

Chemistry
2 answers:
Grace [21]2 years ago
6 0

Answer:

\huge\boxed{\sf t = 50 \ seconds}

Explanation:

<h3><u>Given data:</u></h3>

Acceleration = a = 0.4 m/s²

Initial Speed = V_i = 20 m/s

Final Speed = V_f = 40 m/s

<h3><u>Required:</u></h3>

Time = t = ?

<h3><u>Formula:</u></h3>

\displaystyle a =\frac{V_f-V_i}{t}

<h3><u>Solution:</u></h3>

Rearranging formula for t

\displaystyle t =\frac{V_f-V_i}{a} \\\\t = \frac{40-20}{0.4} \\\\t = \frac{20}{0.4} \\\\\boxed{t = 50 \ seconds}\\\\\rule[225]{225}{2}

joja [24]2 years ago
4 0

Answer:

50 seconds

Explanation:

Equation used :

<u><em>v = u + at</em></u>

<u><em /></u>

Given :

⇒ a = 0.4 m/s²

⇒ u = 20 m/s

⇒ v = 40 m/s

Solving :

⇒ 40 = 20 + 0.4t

⇒ 0.4t = 20

⇒ t = 20/0.4

⇒ t = 50 seconds

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How much volume would a 834.01g pile of sugar have given that it has a density of 1.59g/mL?
boyakko [2]

Answer:

v = 534.5mL

m = 597.15g

Density = 9.23g/mL

Density = 9.125g/mL

Explanation:

Density = mass/ volume

For the first question

Density = 1.59g/mL

Mass = 834.01g

Volume = ?

Using the above formula we have 1.59 = 834.01/v

v = 834.01/1.59

v = 534.5mL

For the second question

Density =0.9167g/mL

Volume = 651.41mL

Mass =?

Using the above formula we have

0.9167 =m/651.41

Cross multiply

m = 0.9167 x 651.41

m = 597.15g

For the third question

Mass =803.44g

Volume=87.03mL

Density =?

Density = 803.44/87.03

= 9.23g/mL

For the fourth

Density = 56.85/6.23

= 9.125g/mL

7 0
3 years ago
if 30.0L of oxygen are cooled from 200 degrees celsius to 1 degree celsius at constant pressure, what is the new volume of oxyge
Sergio039 [100]

Answer: 18.65L

Explanation:

Given that,

Original volume of oxygen (V1) = 30.0L

Original temperature of oxygen (T1) = 200°C

[Convert temperature in Celsius to Kelvin by adding 273.

So, (200°C + 273 = 473K)]

New volume of oxygen V2 = ?

New temperature of oxygen T2 = 1°C

(1°C + 273 = 274K)

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

30.0L/473K = V2/294K

To get the value of V2, cross multiply

30.0L x 294K = 473K x V2

8820L•K = 473K•V2

Divide both sides by 473K

8820L•K / 473K = 473K•V2/473K

18.65L = V2

Thus, the new volume of oxygen is 18.65 liters.

5 0
3 years ago
Please help me! I will fail science if I don’t finish this test :(
Tasya [4]

Answer:

<h2>A. Mercury's orbit is shorter than Earth</h2>
6 0
3 years ago
Irrigation is a method used to water farm land. Identify two effects irrigation has on the water cycle and environment. A Irriga
sergiy2304 [10]

Answer:

A and C

Explanation:

6 0
3 years ago
If the concentration of the stock (provided) Cu(NH3)42 was 0.041 M, what concentration will the Cu2 be in beaker?
kodGreya [7K]

Answer:

[Cu^{2+}]=0.041 M

Explanation:

Hello!

In this case, since the molarity of a solution is defined in terms of the moles of the solute and the volume of solution, given that the concentration of Cu(NH₃)₄²⁺ is 0.041 M, and there is only one copper atom per Cu(NH₃)₄²⁺ ion, we can compute the concentration of Cu²⁺ as shown below:

[Cu^{2+}]=0.041\frac{molCu(NH_3)_4^{2+}}{L}*\frac{1molCu^{2+}}{1molCu(NH_3)_4^{2+}} =0.041 \frac{molCu(NH_3)_4^{2+}}{L}

[Cu^{2+}]=0.041 M

Best regards!

6 0
3 years ago
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