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Tema [17]
3 years ago
7

What is the predominant intermolecular force in the liquid state of each of these compounds: water (h2o), carbon tetrafluoride (

cf4), and dichloromethane (ch2cl2)?
Chemistry
2 answers:
alexandr402 [8]3 years ago
6 0
Water: hydrogen bonding
carbon tetrafluoride: dispersion or Van del Waals
dichloromethane: dipole-dipole
gregori [183]3 years ago
5 0

Answer: Water- hydrogen bonding

Carbon tetraflouride- dispersion forces

Dichloromethane- dispersion forces

Explanation:

Hydrogen bonding exists when hydrogen is bonded to an electronegative element. This results in a permanent dipole in the molecule. However, nonpolar molecules such as dichloromethane are held only by the weak dispersion forces.

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A compound containing Na, C, and O is found to have 1.06 mol Na, 0.528 mol C, and 1.59 mol O. What is the empirical formula of t
Effectus [21]

Given :

Moles of Na : 1.06

Moles of C : 0.528

Moles of O : 1.59

To Find :

The empirical formula of the compound.

Solution :

Dividing moles of each atom with the smallest one i.e 0.528 .

So,

Na : 1.06/0.528 = 2.007 ≈ 2

C : 0.528/0.528 = 1

O : 1.59/0.528 = 3.011 ≈ 3

Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.

So, empirical formula is Na_2CO_3 .

Hence, this is the required solution.

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2 years ago
How many formula units are present in 40.0 grams of Cu2S?
11Alexandr11 [23.1K]

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4 0
2 years ago
How many parts per million of lead is found in 250 ml of water if there is 1.30g of lead in the water? 1ml=1g
SSSSS [86.1K]

Answer:

5200 ppm

Explanation:

As per the definition, parts per million of a contaminant is a measure of the amount of mass of contaminant present per million amount of the solution. It is denoted by ppm.

Given in the question,

Water = 250 ml = 250 g

Lead = 1.30 g

So,

ppm of Lead = \frac{Lead}{Water} \times 10^6 = \frac{1.30}{250} \times 10^6 = 5200 ppm

So, as calculated above, there is 5200 ppm of lead present in 250 ml of water.

6 0
2 years ago
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