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Montano1993 [528]
1 year ago
14

A 400. 0 g sample of liquid water is at 30. 0 ºc. how many joules of energy are required to raise the temperature of the water t

o 45. 0 ºc?
Chemistry
1 answer:
Agata [3.3K]1 year ago
7 0

Energy required to raise the temperature from 35°C - 45 °C= 25116 J.

specific heat, the quantity of warmth required to raise the temperature of one gram of a substance by means of one Celsius degree. The units of precise warmth are generally energy or joules consistent with gram according to Celsius diploma. for instance, the unique warmth of water is 1 calorie (or 4.186 joules) according to gram in step with Celsius degree.

solving,

Sample of liquid = 400. 0 g

temperature = 30. 0 ºc

joules of energy are required to raise the temperature of the water to 45. 0 ºc

therefore rise in temperature 45 - 30 = 15°C

Specific heat capacity = 4.186 J/g m °C

In kelvin = 273 + 15 = 288

          = ∴ energy required = Q = m s ( t final - t initial)

            =  400*4.186 * 15

           = 25116 joule

Learn more about specific heat here:-brainly.com/question/21406849

#SPJ4

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LiRa [457]

P 15 atm

V₁ = 12x103 m3 -3 3 V₁ = 12x10 m" T₁ = 25°c T= 28815 K

P₁ = 1.52x10 Pa

Now, Finel quantities, T₂ = 35°C = 308.15 °K

V2= 851 = -3 3

Now

by ideal gas equation

P2Y2 T2

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1152 X106 x 12x16 3 x 308115 8,5×103 x 288,15 = Pa

=

21294×10 Pa

P₂ = 21264 Atm

final

pressure will be

21264 Adm.

Please check the attached file for a brief answer.

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brainly.com/question/24746268

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