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Marta_Voda [28]
3 years ago
8

You have decided to purchase a car for $22,346.16. The credit union requires a 10% down payment and will finance the

Mathematics
2 answers:
Aleks04 [339]3 years ago
6 0

Answer:

b.

$24,169.60

Step-by-step explanation:

hope it helps :)

sukhopar [10]3 years ago
5 0

Answer:

(b) \$24,169.60

Step-by-step explanation:

Given:  Cost of car is \$22,346.16

            Sales tax is 7.6\%    

             The license and title  charges are \$125.13

To find: The amount that the credit union will finance.

Solution:

We have,  

Cost of car=\$22,346.16  

Sales tax is 7.6\% of \$22,346.16

Therefore,  

sales tax =\frac{7.6}{100}\times22,346.16=\$1698.31

The license and title  charges =\$125.13

Now, the amount that the credit union will finance is

cost of car+sales tax+the license and title  charges

=\$22346.16+\$1698.31+\$125.13

=\$24,169.60

Hence, the amount that the credit union will finance is \$24,169.60.

So, (b) \$24,169.60 is correct.

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-10.7474..... as a fraction
kondaur [170]

In fraction, it would be:

-107474/10000

6 0
3 years ago
What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?
GREYUIT [131]
Sum is
S_{n}=\frac{a_{1}(1-r^{n})}{1-r}

r=common ratio
a1=first term
it looks like 2^0=1 is the first term aka a1
it goes to the 9th term (2^9)

sub
S_{9}=\frac{1(1-(2)^{9})}{1-2}
S_{9}=\frac{1-512}{-1}
S_{9}=\frac{-511}{-1}
S_{9}=511

4 0
3 years ago
Read 2 more answers
Solve for x and y<br><br>6/x+2y + 5/x-2y = -3 ;<br>3/x+2y + 7/x-2y = -6​
Radda [10]

Step-by-step explanation:

Let

{1/(x+2y)} = u -----Eqn(1)

{1/(x-2y)} = v ------Eqn(2)

So, given equation can be rewritten as

⇛6u + 5v = -3 ---Eqn(3)

⇛3u + 7v = -6 -----Eqn(4)

On multiply equation (4) by 2, we get

⇛6u + 14v = -12 -----Eqn(5)

On subtracting equation (3) from equation (5), we get

⇛9v = -9

⇛v = -9/9

⇛v = -1 ----Eqn(6)

Put value of v in equation (3), we get

6u + 5v = -3

⇛6u + 5 * (-1) = -3

⇛6u -5 = -3

⇛6u = -3 + 5

⇛6u = 2

⇛u = 2/6

⇛u = (2÷2)/(6÷2)

⇛u = 1/3 -----Eqn(7)

Now, substituting value of u and v in equation (1) and equation (2), we get

{1/(x+2y)} = 1/3 and {1/(x-2y)} = -1

⇛x + 2y = 3 -----Eqn(8)

⇛x - 2y = -1 -------Eqn(9)

Now, add equation (8) and equation (9) , we get

⇛2x = 2

⇛x = 2/2

<h3>⇛x = 1 -----Eqn(10)</h3>

On substituting x = 1 in equation (8), we get

x + 2y = 3

⇛ 1 + 2y = 3

⇛2y = 3 - 1

⇛2y = 2

⇛y = 2/2

<h3>⇛y = 1 ------Eqn(11)</h3>

Therefore, x = 1 and y = 1

<u>Answer</u><u>:</u> Hence the value of x and y is 1 and 1.

8 0
2 years ago
Please help me out !!
Dmitrij [34]
<h3>Solution:</h3>

\huge \pink {\tt {{128}^{ \frac{3}{7} }  =  \sqrt[7]{ {128}^{3} }  =  {2}^{3}  }}

\huge \pink {\tt {= 8}}

<h2>Answer:</h2>

\huge \purple {\tt {8 \: is \: the \: answer}}

8 0
3 years ago
HELP!<br>What is the distance between points (6, -9) and (-3, 4)?​
ra1l [238]

Answer:

4 or \sqrt{250}

Step-by-step explanation:

I used M a t h w a y. it's really helpful. Good luck.

7 0
3 years ago
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