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Zinaida [17]
3 years ago
6

4 FeCO3 + O2 --> 2 Fe2O3 + 4CO2

Chemistry
1 answer:
Andre45 [30]3 years ago
4 0

The percentage yield of the reaction : 93.3%

Mass of FeCO₃ 2310.44 g

<h3>Further explanation </h3>

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction

4 FeCO₃ + O₂ ⇒ 2 Fe₂O₃ + 4CO₂

MW FeCO₃ : 115,854 g/mol

MW Fe₂O₃ : 159,69 g/mol

  • mol FeCO₃

\tt \dfrac{35}{115.854}=0.302

  • mol Fe₂O₃

\tt \dfrac{2}{4}\times 0.302=0.151

  • mass Fe₂O₃

\tt 0.151\times 159.69=24.113~g

  • percent yield

\tt \dfrac{22.5}{24.113}\times 100\%=93.3\%

mol of 1 kg Fe₂O₃ = 1000 g

\tt \dfrac{1000}{159.69}=6.262

mol of FeCO₃

\tt \dfrac{4}{2}\times 6.262=12.524

mass of FeCO₃

\tt 12.524\times 115.854=1450.955~g

a purity of 62.8%

\tt \dfrac{100}{62.8} \times 1450.955=2310.44~g

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