Question

4 FeCO3 + O2 --> 2 Fe2O3 + 4CO2

Answer 1

The percentage yield of the reaction : 93.3%

Mass of FeCO₃ 2310.44 g

Further explanation

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction

4 FeCO₃ + O₂ ⇒ 2 Fe₂O₃ + 4CO₂

MW FeCO₃ : 115,854 g/mol

MW Fe₂O₃ : 159,69 g/mol

• mol FeCO₃

$\tt \dfrac{35}{115.854}=0.302$

• mol Fe₂O₃

$\tt \dfrac{2}{4}\times 0.302=0.151$

• mass Fe₂O₃

$\tt 0.151\times 159.69=24.113~g$

• percent yield

$\tt \dfrac{22.5}{24.113}\times 100\%=93.3\%$

mol of 1 kg Fe₂O₃ = 1000 g

$\tt \dfrac{1000}{159.69}=6.262$

mol of FeCO₃

$\tt \dfrac{4}{2}\times 6.262=12.524$

mass of FeCO₃

$\tt 12.524\times 115.854=1450.955~g$

a purity of 62.8%

$\tt \dfrac{100}{62.8} \times 1450.955=2310.44~g$