Missing question: What is the rate constant for the reaction?
<span>[RS2](mol L-1) Rate (mol/(L·s))
0.150 0.0394
0.250 0.109
0.350 0.214
0.500 0.438</span>
Chemical reaction: 3RS₂ → 3R + 6S.
Compare second and fourth experiment, when concentration is doubled, rate of concentration is increaced by four. So rate is:
rate = k·[RS₂]².
k = 0,438 ÷ (0,500)².
k = 1,75 L/mol·s.
Answer: The molar mass of the gas is 31.6 g/mol
Explanation:
According to ideal gas equation:
P = pressure of gas = 3.0 atm
V = Volume of gas = 25.0 L
n = number of moles = ?
R = gas constant =
T =temperature =
Moles =
The molar mass of the gas is 31.6 g/mol
Answer:
an object that is at rest will stay at rest inless a force acts upon it.
An oject that is in motion will not change its velocity unless a force acts upon it.
Answer: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^4
Explanation:
I suggest looking at the electron configuration chart, it has really helped me a lot :)
