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mote1985 [20]
4 years ago
15

Can you help me understand this ? I completely dont understand it ​. i know the tire will burst.

Chemistry
2 answers:
sergejj [24]4 years ago
8 0

Answer:

There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.

1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol

2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa

3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst. 4. Reduce pressure way below the limit 269 kPa.

Explanation:

icang [17]4 years ago
6 0

Answer:

There is only one formula to use and we should assume ideal gas. This equation is: PV=nRT. For the following questions manipulate this equation to get the answer.

1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol

2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa

3. Since the answer in #2 is more than 269 kPa, then the tires will likely burst. 4. Reduce pressure way below the limit 269 kPa.

Explanation:

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4 0
3 years ago
Which element when combined with fluorine would form a ionic compound
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8 0
3 years ago
It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0?C to 24.3?C. What is the specific heat for
svet-max [94.6K]

Answer:

c = 0.377 J/g.°C

c = 0.2350 J/g.°C

J = 27.3 J

Explanation:

We can calculate the heat (Q) absorbed or released by a substance using the following expression.

Q = c × m × ΔT

where,

c: specific heat

m: mass

ΔT: change in the temperature

<em>It takes 49.0J to raise the temperature of an 11.5g piece of unknown metal from 13.0°C to 24.3°C. What is the specific heat for the metal? Express your answer numerically, in J/g.°C</em>

Q = c × m × ΔT

49.0 J = c × 11.5 g × (24.3°C - 13.0°C)

c = 0.377 J/g.°C

<em>The molar heat capacity of silver is 25.35 J/mol.°C. How much energy would it take to raise the temperature of 11.5g of silver by 10.1°C? Express your answer numerically, in Joules. What is the specific heat of silver?</em>

<em />

The molar mass of silver is 107.87 g/mol. The specific heat of silver is:

\frac{25.35J}{mol.\° C} .\frac{mol}{107.87g} =0.2350J/g.\° C

Q = c × m × ΔT

Q = (0.2350 J/g.°C) × 11.5 g × 10.1°C = 27.3 J

5 0
3 years ago
How many moles of Ca(OH)2 are in 3.5kg of Ca(OH)2? Answer in units of mole
Kobotan [32]
First, you need to convert kg to g. 
So, 1 kg =1000g.
3.5 x 1000 = 3500g Ca(OH)2

We need to know the molar mass of Ca(OH)2. 
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O=2(15.999)
H=2(1.0079)

Add them all together and you get 74.0938 g.

Put it in the formula from mass to moles. 

# of moles = grams Ca(OH)2 x 1 mol Ca(OH)2
                                                  --------------------
                                                  molar mass Ca(OH)2

3500 g Ca(OH)2 x 1 mol Ca(OH)2
                              ---------------------
                             74.0938 g Ca(OH)2

So divide 1/74.0938 and multiply by 3500.

You will get about 47.24 moles Ca(OH)2.

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
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