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denis23 [38]
2 years ago
8

What volume is occupied by 16.4 g of mercury? The density of mercury is 13.6 g/mL

Chemistry
1 answer:
NeTakaya2 years ago
3 0

Answer:

Brhrhrhrhhrhrhry hehhehdhdhhehehebebebbendjkdjdjfjcjbsksoejejjdnd

Explanation:

Dmdmsnsjsbbs नमस्कार ndjdjdjdjdjdjdjdhdjdjd ndndjdhdjdjdj ndjdjdjdjdjdjdjdhdjdjd ndndjd

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Accuracy vs. Precision
Oksi-84 [34.3K]

Answer:

Accuracy is the closeness to the specific target and precision is the closeness of the measurements to each other.

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3 years ago
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Examples of a pure substances
DiKsa [7]

Answer:

Explanation:

Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements.

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2 years ago
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What geometry does VSEPR predict for the central atom in NCl3
Archy [21]

Answer:

Tetrahedral electron geometry and trigonal pyramidal molecular geometry.

Explanation:

The Lewis structure is shown in Figure 1.

The central N atom has three bonding pairs and one lone pair, for <em>four electron groups</em>.

VSEPR theory predicts a tetrahedral electron geometry with bond angles of 109.5°.

We do not count the lone pair in determining the molecular shape.

The molecular geometry is trigonal pyramidal (see Figure 2).

5 0
2 years ago
Which metal will react spontaneously with Cu2+ (aq) at 25°C?
Gwar [14]

Answer:

Mg  

Explanation:

The standard reduction potentials are

                                              <u>E°/V </u>

Au³⁺(aq ) + 3e⁻  ⟶  Au(s);     1.42

Hg²⁺(aq)  + 2e⁻  ⟶  Hg(l);     0.85

Ag⁺(aq)    +   e⁻  ⟶  Ag(s);    0.80

Cu²⁺(aq)   + 2e⁻ ⟶  Cu(s);   0.34

Mg2+(aq) + 2e- ⟶  Mg(s);   -2.38

The more negative the standard reduction potential, the stronger the metal is as a reducing agent.

Mg is the only metal with a standard reduction potential lower than that of Cu, so

Only Mg will react spontaneously with Cu²⁺.

 

5 0
2 years ago
Read 2 more answers
Need help setting the problem up
Sveta_85 [38]

Answer:

4.0 moles

Explanation:

The following data were obtained from the question:

Volume (V) = 12L

Pressure = 5.6 atm

Temperature (T) = 205K

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

Using the ideal gas equation: PV = nRT, the number of mole of the gas can be obtained as follow

PV = nRT

5.6 x 12 = n x 0.08206 x 205

Divide both side by 0.08206 x 205

n = (5.6 x 12)/(0.08206 x 205)

n = 4.0 moles

Therefore, the number of mole of the gas is 4.0 moles

5 0
2 years ago
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