Image attached pls help 40 points
2 answers:
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Answer:
We conclude that her students, on average, do not take 30 minutes on the quiz, contrary to what the textbook company states.
Step-by-step explanation:
We are given;
Population mean; μ = 30 minutes
Population standard deviation; σ = 3 minutes
Sample size; n = 10
Sample mean; x¯ = 25
Significance level = 5% = 0.05
Let's define the hypotheses;
Null hypothesis; H0: μ = 30
Alternative hypothesis: Ha: μ ≠ 30
Let's find the test statistic;
z = (x¯ - μ)/(σ/√n)
z = (25 - 30)/(3/√10)
z = -5.27
From online p-value from z-score calculator attached using, z = -5.27, significance level = 0.05, two tailed hypothesis, we have;
p < 0.00001
This is less than the significance level, and so we will reject the null hypothesis and conclude that Her students, on average, do not take 30 minutes on the quiz, contrary to what the textbook company stated.
