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3 years ago

Felicia filled the bathroom sink with water. Is the amount more than

Mathematics

1 answer:

stiv31 [10]3 years ago

8 0

It’s 100% more than 1 liter

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during 2002 the average person ate 220.8 pounds of meat how much meat does a family of 3 people eat in one year

7nadin3 [17]

You do 220.8 times 3. That's 662.4 pounds of meat in a year.

6 0

3 years ago

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Oaklands zoo has two elephants. The male elephant weighs 3/4 a ton and the female elephant weighs 1/4 of a ton. How much does th

SOVA2 [1]

so if you take away 1/4 from 3/4 you will get 2/4

3/4 - 1/4 = 2/4 or 1/2

so the male elephant weights 1/2 a ton more than the female

8 0

3 years ago

The larger of two supplementary angles is 6 less than 5 times the smaller. Find the measure of the two angles.

zimovet [89]

Answer:

Step-by-step explanation:

Let the two angles be x and y

Then: y = 5x - 6

And x + y = 180° (the of supplementary angle is 180°)

Putting y = 5x - 6

x + 5x - 6 = 180

6x = 180 + 6

6x = 186

x = 186/6

x = 31°

And y = 5x - 6

y = 5(31) - 6

y = 155 - 6

y = 149°

The angles are 31° and 149°

6 0

3 years ago

Which fraction is equal to 15%

Andreas93 [3]

Answer:

15/100 this is the fraction for 15%

7 0

3 years ago

* Some amount of billiard balls were arranged in an equilateral triangle. And 5 balls were extra. When the same set of billiard

Agata [3.3K]

Lets say billiard balls are arranged in rows to form an equilateral triangle, then the first row consists of 1 ball, second row consists of 2 balls, and third row consists of 3 balls, and so on. So there must be $n$ balls in the $n^{th}$ row.

So, the total number of balls that forms the equilateral triangle with $n$ rows is:

$1+2+3+4+5+....+n=\frac{n(n+1)}{2}$

Let $x_1$ and $x_2$ be the total number of balls in the first and second arrangements respectively.

Then,

$x_1=\frac{n(n+1)}{2} +5$

It has been said that there were 11 lesser balls in the second arrangement:

$x_2=\frac{1+(n+1)}{2} \times (n+1)-11=(n+1) \times \frac{(n+2)}{2} -11$

Since, $x_1=x_2$

$\frac{(n+1)}{2} \times n+5=\frac{(n+2)}{2} \times(n+1)-11$

multiplying both the sides by 2

$(n+1)\times n+10=(n+2)(n+1)-22$

$n+n^2=n^2+n+2n+2-22-10$

$2n=22+10-2$

$2n=30$

$n=15$

Therefore,

$x_1=\frac{(n+1)}{2}\times n+5=\frac{15+1}{2} \times 15+5=125$

So, there were 125 balls at the set.

4 0

3 years ago

Read 2 more answers