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Otrada [13]
3 years ago
9

Anybody wanna help me with number 22? (Chemistry)

Chemistry
1 answer:
Inga [223]3 years ago
8 0

Answer:

Rutherford atomic model of atom

Explanation:

lord lutherford

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What are bacteria? Chapter 7 lesson 2 AYU
Maru [420]

Answer:

a group of unicellular microorganisms

7 0
3 years ago
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8. A party-supply store sells a helium-gas
MatroZZZ [7]

Answer:

P₂= 116.7 atm

Explanation:

Here apply the Boyle's law equations that states :at constant temperature the volume of a dry mass of a gas is inversely proportional to its pressure.

This is simplified as;

P₁V₁=P₂V₂ where P is pressure and V is volume

Given that;

P₁=1

V₁=1.81 m³

P₂=?

V₂=1.55*10^-2 m³

Apply the formula

1*1.81 =P₂*1.55*10^-2 m³

1.81/1.55*10^-2  =P₂

P₂= 116.7 atm

7 0
3 years ago
Write the products of these double-replacement reaction. Then balance each equation. a) NaOH(aq) + Fe(NO3)3 (aq)---> Iron (II
pashok25 [27]

Answer:

3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)

Explanation:

Step 1: RxN

NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + NaNO₃ (aq)

Step 2: Balance RxN

We need 3 OH's on both sides.

We also need 3 NO₃'s on both side.

  • This will make it so we also need 3 Na's on both side

3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)

6 0
3 years ago
A 5 mL sample of an unknown liquid is placed into a 250 mL flask that has had all of the air removed. The pressure measured in t
Brrunno [24]

Answer:

See explanation below

Explanation:

In this case, we can use the Boyle's law. Assuming that the temperature of both trial remains constant, then:

P₁V₁ = P₂V₂    (1)

You should note that this expression is usable when you are dealing with gases. However, we can treat this unknown liquid as a gas, because all the air on the flask is removed, and we can assume that the liquid can behave like an ideal gas.

So using the above expression, we can solve for P₂:

P₂ = P₁V₁ / V₂    (2)

In this case, we already have the values of presures and volume, so replacing in this expression:

P₂ = 34.5 * 5 / 214

<h2>P₂ = 0.806 kPa</h2>

This should be the pressure of the liquid.

Hope this helps

8 0
3 years ago
H+ ions increase in concentration at lower pH values. Calculate how many more H+ ions there are in a solution at a pH = 2 than i
joja [24]

The H⁺ ion concentration can be calculated from pH values using the following equation:

pH=-log[H⁺]

1.) Given pH = 2

Using the above equation, 2 = - log [H⁺]

Therefore, [H⁺] = 10⁻² mol/L

2.) Given pH = 6

Using the same equation, we have 6 = - log [H⁺]

Hence, [H⁺] = 10⁻⁶ mol/L

3.) Taking the ratio of [H⁺] for pH = 2 and pH = 6, we have

\frac{10^{-2} }{10^{-6} } = 10⁴

So, there are 10,000 times more H⁺ ions in a solution of pH = 2 than that of pH = 6.

6 0
3 years ago
Read 2 more answers
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