Answer:
a group of unicellular microorganisms
Answer:
P₂= 116.7 atm
Explanation:
Here apply the Boyle's law equations that states :at constant temperature the volume of a dry mass of a gas is inversely proportional to its pressure.
This is simplified as;
P₁V₁=P₂V₂ where P is pressure and V is volume
Given that;
P₁=1
V₁=1.81 m³
P₂=?
V₂=1.55*10^-2 m³
Apply the formula
1*1.81 =P₂*1.55*10^-2 m³
1.81/1.55*10^-2 =P₂
P₂= 116.7 atm
Answer:
3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)
Explanation:
Step 1: RxN
NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + NaNO₃ (aq)
Step 2: Balance RxN
We need 3 OH's on both sides.
We also need 3 NO₃'s on both side.
- This will make it so we also need 3 Na's on both side
3NaOH (aq) + Fe(NO₃)₃ (aq) → Fe(OH)₃ (s) + 3NaNO₃ (aq)
Answer:
See explanation below
Explanation:
In this case, we can use the Boyle's law. Assuming that the temperature of both trial remains constant, then:
P₁V₁ = P₂V₂ (1)
You should note that this expression is usable when you are dealing with gases. However, we can treat this unknown liquid as a gas, because all the air on the flask is removed, and we can assume that the liquid can behave like an ideal gas.
So using the above expression, we can solve for P₂:
P₂ = P₁V₁ / V₂ (2)
In this case, we already have the values of presures and volume, so replacing in this expression:
P₂ = 34.5 * 5 / 214
<h2>
P₂ = 0.806 kPa</h2>
This should be the pressure of the liquid.
Hope this helps
The H⁺ ion concentration can be calculated from pH values using the following equation:
![pH=-log[H⁺]](https://tex.z-dn.net/?f=pH%3D-log%5BH%E2%81%BA%5D)
1.) Given pH = 2
Using the above equation, 2 = - log [H⁺]
Therefore, [H⁺] = 10⁻² mol/L
2.) Given pH = 6
Using the same equation, we have 6 = - log [H⁺]
Hence, [H⁺] = 10⁻⁶ mol/L
3.) Taking the ratio of [H⁺] for pH = 2 and pH = 6, we have
= 10⁴
So, there are 10,000 times more H⁺ ions in a solution of pH = 2 than that of pH = 6.
