I would pick the shrimp because it has the most chromosomes so that is more protein we when you eat shrimp you are getting the most protein out of all of them
Explanation: put this in your own words please
A) when the balanced equation of the reaction is:
H2CO3(aq) → HCO3 -(aq) + (H+)
and when we have Ka = 4.3 x10^-7 & PH = 7.4
So first we will get PKa = -㏒ Ka
PKa = -㏒(4.3x10^-7) = 6.37 by substitution with Pka value in the following formula:
PH = Pka + ㏒[salt/acid]
PH= PKa + ㏒[HCO3-]/[H2CO3]
㏒[HCO3-]/[H2CO3] = PH-Pka
[HCO3-] /[H2CO3] = 10^(7.4 - 6.37)
∴[HCO3-]/[H2CO3] = 11.7
∴[H2CO3]/[HCO3-] = 1/11.7 = 0.09
B) when The balanced equation for this reaction is:
H2PO42-(aq) → HPO4-(aq) + H+
and when we have Ka = 6.2x10^-8 & PH = 7.15
So Pka= -㏒Ka = -㏒(6.2x10^-8) = 7.2 by substitution by Pka value in the following formula:
PH = Pka + ㏒[salt/acid]
7.15= 7.2 + ㏒[HPO4]/[H2PO4]
-0.05 = ㏒[HPO4]/[H2PO4]
∴[HPO4]/[H2PO4] = 10^-0.05 = 0.89
∴[H2PO4]/[HPO4] = 1/0.89 = 1.12
c) H3PO4(aq) ↔ H2PO-(aq) + H+
the answer is: because we have Ka =7.5x10^-3 and it is a high value of Ka to make a good buffer, also we need a week acid with th salt of the week acid as H3PO4 is a strong acid so it does'nt make a goof buffer.
Answer:
112.540 gram of N2
Explanation:
From the balanced chemical equation
N2+3H2----->2NH3
It means that 1 mole of Nitrogen needs 3 moles of hydrogen
In term of mass,we can say that
6.048 gram of H2 needs 28.01 gram of N2
or, 1 gram of H2 needs (28.01/6.048) gram of N2
and 24.3gram of H2 needs (24.3*28.01/6.048) gram of N2
=112.540 gram of N2
Molar Mass and Avogadro's constant
Explanation:
- Molar mass is calculated by using the mass chemical compound, and the amount of substance. So, to find the molar mass of a particular element or the compound, we have to divide the mass of the given chemical compound or the chemical element( grams) by amount of substance ( moles).
- We can add the standard atomic mass (g/mole) of constituent atoms to find the molar mass of the compound.
- To convert atoms to molecules, we have to dive the number of atoms by Avogadro constant which is 6.022 x 10^23.
