Zero (0) molecules of glucose are produced.
For a gas containing 80% CH4 and 20% He is sent through a quart diffusion tube, the composition is mathematically given as
%He=12.5%
%CH4=87.5%
<h3>What is the
composition of the waste gas if 100 kg moles of gas are processed per minute?</h3>
Generally, the equation for the Material balance is mathematically given as
F=R+W
Therefore
100=0.20*1000+W
W=80kmol/min
In conclusion, waste gas compose
2.0/100*100=50/100*20+%*80
Hence
%He=12.5%
%CH4=87.5%
Read more about Chemical reaction
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Answer:A property that changes if the amount of substance changes
Explanation:
This is the answer
Explanation:
Mass of fructose = 33.56 g
Mass of water = 18.88 g
Total mass of the solution = Mass of fructose + Mass of water = M
M = 33.56 g + 18.88 g =52.44 g
Volume of the solution = V = 40.00 mL
Density =
a) Density of the solution:

b) Molar mass of fructose = 180.16 g/mol
Moles of fructose = 
Molar mass of water = 18.02 g/mol
Moles of water= 
Mole fraction of fructose in this solution:


Mole fraction of water = 
c) Average molar mass of of the solution:
=

d) Mass of 1 mole of solution = 42.50 g/mol
Density of the solution = 1.311 g/mL
d) Specific molar volume of the solution:


Answer:

Explanation:
Hello there!
In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

In terms of mass, specific heat and temperature change is:

Now, solve for the final temperature, as follows:

Then, plug in the masses, specific heat and temperatures to obtain:

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.
Regards!