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alekssr [168]
3 years ago
11

If barium was to react with oxygen to form ionic compounds, how many oxygen atoms would be needed? Explain.

Chemistry
1 answer:
Dafna11 [192]3 years ago
8 0

Answer:

1 oxygen atoms

Explanation:

When barium combines with oxygen to form an ionic compound, it will only require just an oxygen atom.

An ionic compound is formed due to the electrostatic attraction between oppositely charged ions

A metal loses electrons to be gained by the non - metal and in the process they attract each other with a force.

 Barium has two valence electrons, to be stable, it loses the two;

 Oxygen has six valence electrons, to be stable it will gain two valence electrons to form an octet.

 So;

     One barium atom will successfully bind with One oxygen atom to form

               BaO

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How can one kg of iron melt more ice than 1 kg lead at 100 °C
Vanyuwa [196]

Answer:

Due to the specific heat capacity of iron, 0.444 J/(g·°C), is more than the specific heat capacity for lead, 0.160 J/(g·°C)

Explanation:

The given parameters are;

The metals provided to melt the ice and their temperature includes;

One kg (1000 g) of iron;

Specific heat capacity = 0.444 J/(g·°C)

Temperature = 100°C

1 kg (1000 g) of lead

Specific heat capacity = 0.160 J/(g·°C)

Temperature = 100°C

Therefore, the heat provided to the ice of mass m, and latent heat of 334 J/g at 0°C by the metals are as follows;

For iron, we have;

ΔQ = Mass × Specific heat capacity × Temperature change

ΔQ_{iron} = Heat obtained from the iron by the ice

ΔQ_{iron} = 0.444 m × 1000 × (100 - 0) = 44400 J

Heat absorbed by the ice for melting, H_l = Heat obtained from the iron

∴ Heat absorbed by the ice for melting, H_l = Mass of ice × Latent heat of ice

H_l = Mass of ice × 334 J/g = 44400 J

Mass of ice melted by the iron = 44400 J/334 (J/g) ≈ 132.9 g

Mass of ice melted by the iron ≈ 132.9 g

For lead, we have;

ΔQ = Mass × Specific heat capacity × Temperature change

ΔQ_{lead} = Heat obtained from the iron by the ice

ΔQ_{lead} = 0.160 m × 1000 × (100 - 0) = 16000 J

Heat absorbed by the ice for melting, H_l = Heat obtained from the iron

∴ Heat absorbed by the ice for melting, H_l = Mass of ice × Latent heat of ice

H_l = Mass of ice × 334 J/g = 16000 J

Mass of ice melted by the lead = 16000 J/334 (J/g) ≈ 47.9 g

Mass of ice melted by the lead ≈ 47.9 g

Therefore, mass of  ice melted by the iron, approximately 132.9 g, is more than mass of ice melted by the lead, approximately 47.9 g.

3 0
3 years ago
What would the Net Ionic Equation be for the following:
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The net equations are obtained from the double displacement of the cations and anions, then balance. 

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</span><span>2NaOH(aq) + H2SO4 (aq) = Na2SO4 (s)+ 2H2O (aq)
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3 years ago
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In a double-replacement reaction, the _____.
givi [52]
 In a double-replacement reaction, the _____.?


There are many more interesting things to ask about double replacement reactions than are contained in the list given here. But the only correct choice is: 

C.reactants are two ionic compounds

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I think that it is shear adhesion
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