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otez555 [7]
3 years ago
7

Question below, please answer

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

Answer:

D.

Step-by-step explanation:

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What is the value of this expression if h<br> = 8,j = -1, and k<br> =<br> -12
Rashid [163]

Answer:

12

Step-by-step explanation:

The given expression is :

\dfrac{j^3k}{h^0}

We need to find the value of this expression when h = 8, j = -1 and k = -12.

Put all the values in the given expression.

\dfrac{j^3k}{h^0}\\\\=\dfrac{(-1)^3\times (-12)}{(8)^0}\\\\=\dfrac{-1\times -12}{1}\\\\=12

So, the value of the given expression is 12.

7 0
3 years ago
Can you show all steps to simplify (3x-4)+(x+3)^2
ella [17]
<span>(3x-4)+(x+3)^2
= 3x - 4 + x^2 + 6x + 9 .........(expand using (a+b)^2 = a^2 + 2ab + b^2)
= x^2 + 9x  + 5 ..........(combine like terms and simplify)

hope that  helps</span>
3 0
3 years ago
1/4(x+3)+3/8x=13/4 SOLVE FOR X
larisa86 [58]
1. First I turned the fractions into decimals, just to make things easier for me.2. That gave me => (.25x)+(.75)+(.375)=(3.25)
3. Then, I combined like terms and move my equation around; so, that gave me (.25x) = (3.25) - (.75) - (.375) and when I solve the right side of the equation it gives me
(.25x) = (2.125)
4. After combining like terms and simplifying (the way I did in step 3), I will divide both sides by .25, to get the value of X alone; so, my equation then looks like => x=8.5

4 0
3 years ago
what is a correct first step in solving the inequality –4(3 – 5x)≥ –6x 9? –12 – 20x ≤ –6x 9 –12 – 20x ≥ –6x 9 –12 20x ≤ –6x 9 –1
suter [353]

we have

-4(3-5x) \geq -6x+9

Step 1

Applying the distributive property in the left side ( Multiply the factors on the left side)

-4(3-5x) \geq -6x+9\\- 4*3+4*5x\geq -6x+9\\-12+20x\geq -6x+9

therefore

<u>the answer is</u>

-12+20x\geq -6x+9

8 0
3 years ago
Read 2 more answers
What number is equivalent to 3/4 b-2/3 b =-9
Shtirlitz [24]
Hi,

b =  - 9 \\ \frac{3}{4}  \times b -  \frac{2}{3}   \\ 0.75 \times  - 9 - 0.67 \\  - 6.75 - 0.67 =   - 7.42

Answer: -7.42

Hope this helps.
r3t40
5 0
3 years ago
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