This is NOT an arithmetic sequence because there is no common difference. It is a geometric sequence because there is a common ratio. Meaning that each term is a constant ratio or multiple of the previous term. The recursive rule for this geometric sequence is:
a(n)=3*a(n-1), a(1)=3
14.1 is the correct answer i just calculated it and then subtracted
Answer:
4b+6 is your answer ☺️☺️☺️
Answer:
- the number is -6.4
- 52 students were in each bus (but one)
- 1 quart
Step-by-step explanation:
1. Let the number be represented by n. Then ten times the number is 10n, and 8 more than that is 10n+8. The problem statement tells us this sum is -56:
10n +8 = -56
10n = -64 . . . . . . . subtract 8 from both sides
n = -6.4 . . . . . . . . . divide both sides by 10
The number is -6.4.
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2. First of all, you can tell there is an issue with this question because the sum of digits of 472 is 13 and the sum of those digits is 4. This tells you that dividing 472 by 9 will give a remainder of 4, not 5. One of the buses will not be filled. (This process of adding digits until you get a single digit is called "casting out nines". The remaining digit is the remainder from division by 9.)
Let b represent the number of students in each bus. Then the problem statement tells us ...
9b + 5 = 472
9b = 467 . . . . . . subtract 5
b = 467/9 = 51 8/9 . . . . almost 52
52 students rode in 8 of the buses; 51 students rode in the last bus.
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3. Let q represent the number of quarts of 6% solution. Then the total amount of Boric Acid in the mix is ...
15%×2 + 6%×q = 12%×(2+q)
Multiplying by 100 to clear the % signs, we have ...
15·2 +6q = 12(2+q)
30 +6q = 24 +12q . . . . . . eliminate parentheses
6 = 6q . . . . . . . . . . . . . . . . subtract 24+6q from both sides
1 = q . . . . . . divide by 6
1 quart of 6% solution must be used.
No, it is not a true proportion.
