Am irrational number is a number that cannot be expressed as a fraction for any integers. numbers of the form,where is the logarithm, are irrational if and are integers, one of which has a prime factor which the other lacks. is irrational for rational
9514 1404 393
Answer:
obtuse
Step-by-step explanation:
The law of cosines tells you ...
b² = a² +c² -2ac·cos(B)
Substituting for a²+c² using the given equation, we have ...
b² = b²·cos(B)² -2ac·cos(B)
We can subtract b² to get a quadratic in standard form for cos(B).
b²·cos(B)² -2ac·cos(B) -b² = 0
Solving this using the quadratic formula gives ...
The fraction ac/b² is always positive, so the term on the right (the square root) is always greater than 1. The value of cos(B) cannot be greater than 1, so the only viable value for cos(B) is ...
The value of the radical is necessarily greater than ac/b², so cos(B) is necessarily negative. When cos(B) < 0, B > 90°. The triangle is obtuse.
Quadratic formula: (-b +/- sqrt(b^2 - 4ac)) / 2a
a = 10
b = -1
c = 9
1 +/- sqrt((-1)^2 - 4(10)(9)) / 2(10)
1 +/- sqrt(1 - 360) / 20
x = 1 +/- sqrt(359i) / 20
Hope this helps!
To find this, first find the factor or rate of which the numbers are moving. To do so do as follows.
subtract 1 from 3
3-1=2
So each number is having 2 added to it.
Now add two to 7 and the numbers afterwards till you get the 12th term
7+2=9
1+3+5+7+9
9+2=11
1+3+5+7+9+11
11+2=13
1+3+5+7+9+11+13
13+2=15
1+3+5+7+9+11+13+15
15+2=17
1+3+5+7+9+11+13+15+17
17+2=19
1+3+5+7+9+11+13+15+17+19
19+2=21
1+3+5+7+9+11+13+15+17+19+21
21+2=23
1+3+5+7+9+11+13+15+17+19+21+23
So 23 is the 12th term
Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
[3.2] [2.7] [2.9] [4.8]
Since they are all of greatest integer functions i.e.
f(x) = [x]
It is known as greatest integer function whose value is always less than or equal to 'x'.
So, [3.2]=3
[2.7]=2
[2.9]=2
[4.8]=4
so, we can see that [2.7] and [2.9] is a equivalent pair.
Hence, Option 'B' is correct.
