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pogonyaev
3 years ago
9

5. The point (-2, -3) is rotated 90 degrees counterclockwise using center (0, 0).

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
7 0

B. (−3, 2)

I think

so plz have a good rest of ur day

34kurt3 years ago
3 0
Answer C

Reflected across the y-axis changes the x- coordinate and the y- coordination remains the same

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A relief fund is set up to collect donations for the families affected by recent storms. A random sample of 400 people shows tha
AVprozaik [17]

Answer:

(0.28-0.18) - 1.96 \sqrt{\frac{0.28(1-0.28)}{200} +\frac{0.18(1-0.18)}{200}}=0.0181  

(0.28-0.18) - 1.96 \sqrt{\frac{0.28(1-0.28)}{200} +\frac{0.18(1-0.18)}{200}}=0.182  

And the 95% confidence interval would be given (0.0181;0.181).  

We are confident at 95% that the difference between the two proportions is between 0.0181 \leq p_B -p_A \leq 0.182

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

p_A represent the real population proportion for telephone  

\hat p_A =0.28 represent the estimated proportion for telephone

n_A=200 is the sample size required for telephone

p_B represent the real population proportion for mail

\hat p_B =0.18 represent the estimated proportion for mail

n_B=200 is the sample size required for mail

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

And replacing into the confidence interval formula we got:  

(0.28-0.18) - 1.96 \sqrt{\frac{0.28(1-0.28)}{200} +\frac{0.18(1-0.18)}{200}}=0.0181  

(0.28-0.18) - 1.96 \sqrt{\frac{0.28(1-0.28)}{200} +\frac{0.18(1-0.18)}{200}}=0.182  

And the 95% confidence interval would be given (0.0181;0.181).  

We are confident at 95% that the difference between the two proportions is between 0.0181 \leq p_B -p_A \leq 0.182

8 0
3 years ago
What is the range of y = sin θ ?
kap26 [50]
The range<span> of a function is the set of all the possible function outputs. </span>We know that <span>sin theta varies between -1 and 1 if we draw a graph. </span><span>According to the graph, the largest number that is an output of </span>g<span> is -1</span><span>, and the smallest number is 1</span><span>. Every number between them is also an output of </span>g<span> for some input. Therefore, the range of </span>g is [-1,1]. <span>

</span>
5 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP WILL MARK BRAINLIEST!!!!!!!solve for x write both solutions. 2x^2+9x+9=0
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2x^2+9x+9=0\\\\2x^2+6x+3x+9=0\\\\2x(x+3)+3(x+3)=0\\\\(x+3)(2x+3)=0\iff x+3=0\ \vee\ 2x+3=0\\\\x+3=0\ \ \ |-3\\x=-3\\\\2x+3=0\ \ \ |-3\\2x=-3\ \ \ |:2\\x=-1.5


Answer:\ \boxed{x=-3\ \vee\ x=-1.5}
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The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible meas
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

so what you nedd otj fkhy is and the anwser is 799

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Is nuclear energy renewable?<br><br> Detailed answer please.
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Answer:

Although nuclear is not renewable, it is clean energy

Step-by-step explanation:

Nuclear power is presently a sustainable energy source but could become completely renewable if the source of uranium changed from mined ore to seawater.

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