All categories

3 years ago

Can a body have zero velocity and finite accelaration in physics

Physics

1 answer:

poizon [28]3 years ago

4 0

Answer:

Yes, a body can have zero velocity but finite acceleration.

For example:

1) At the topmost point when body is thrown vertically upwards

2) At the extreme positions of body under SHM (case of spring as well as that of pendulum)

3) A ball thrown upwards on inclined surface, and at the topmost point when it reverses its velocity is zero but acceleration is not (the acceleration is component of g along inclined plane that is g sinx where x is inclination of the plane with horizontal)

Explanation:

XOXO

Kit

You might be interested in

What beliefs about goverment did early english colonists bring to america?

grigory [225]

A strong belief in democracy and representative government

6 0

3 years ago

A 7.00 kg ball hits a 75.0 kg man standing at rest on ice. The man catches the ball. How fast does the ball need to be moving in

Slav-nsk [51]

<h3>Answer:</h3>

$\displaystyle \overline{v_{1i}} = 35.1429 \ \frac{m}{s}$

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Physics</u>

<u>Momentum</u>

Momentum Formula: $\overline{P} = m \overline{v}$

P is momentum (in kg · m/s)
m is mass (in kg)
v is velocity (in m/s)

Law of Conservation of Momentum: $\sum \overline{P_i} = \sum \overline{P_f}$

States that the sum of initial momentum must equal the sum of final momentum

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[LCM] $\sum \overline{P_i} = \sum \overline{P_f}$ → $m_{1} \overline{v_{1i}} + m_{2} \overline{v_{2i}} = (m_{1} + m_{2}) \overline{v_{f}}$

m₁ (ball) = 7.00 kg

m₂ (man) = 75.0 kg

$\overline{v_{1i}} = ?$

$\overline{v_{2i}} = 0 \ \frac{m}{s}$ (man starts from rest)

$\overline{v_{f}} = 3.00 \ \frac{m}{s}$ (the ball and the man are one mass because the man catches and <em>keeps</em> the ball)

We know no energy is lost because it is a frictionless surface. The collision should be perfectly elastic.

<u>Step 2: Solve</u>

Substitute in variables [Law of Conservation of Momentum]: $\displaystyle (7.00 \ kg) \overline{v_{1i}} + (75.0 \ kg)(0 \ \frac{m}{s}) = (7.00 \ kg + 75.0 \ kg)(3.00 \ \frac{m}{s})$
Multiply: $\displaystyle (7.00 \ kg) \overline{v_{1i}} + 0 = 246 \ kg \cdot \frac{m}{s}$
Simplify: $\displaystyle (7.00 \ kg) \overline{v_{1i}} = 246 \ kg \cdot \frac{m}{s}$
[Division Property of Equality] Isolate unknown: $\displaystyle \overline{v_{1i}} = \frac{246}{7} \ \frac{m}{s}$
[Evaluate] Divide: $\displaystyle \overline{v_{1i}} = 35.1429 \ \frac{m}{s}$