Explanation:
The given data is as follows.
= 400 K, = 500 K,
= 25 kJ = 25000 J (as 1 kJ = 1000 J)
Now, we will calculate the change in entropy as follows.
Putting the given values into the above formula as follows.
=
= 250 J/K
Hence, we can conclude that change in entropy is 250 J/K.
DE = DC + CE
27 = 3v - 30 + 6v - 15
27 = 9v - 45
v = 8
We are given information:
m = 0.0450 kg
Δv = 25.2 m/s
Δt = 1.95 ms = 0.00195s
To find force we use formula:
F = m * a
a is acceleration. To find it we use formula:
a = Δv / Δt
a = 25.2 / 0.00195
a = 12923.1 m/s^2
Now we can find force:
F = 0.0450 * 12923.1
F = 581.5 N
To check the effect of the ball's weight on this movement we need to calculate it and then compare it to this force.
W = m * g
W = 0.0450 * 9.81
W = 0.44145 N
We can see that weight is much smaller than the applied force so it's influence in negligible.
Not sure but a centripetal acceleration.