An object is inside a room that has a constant temperature of 292 K. Via radiation, the object emits three times as much power a
1 answer:
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= Heat released to cold reservoir
= Heat released to hot reservoir
= maximum amount of work
= temperature of cold reservoir
= temperature of hot reservoir
we know that
eq-1
maximum work is given as
=
-
using eq-1
=
-
Answer:
355 m/s
Explanation:
Distance = 605 km
Initial speed = = 284 m/s
Final velocity = = 426 m/s
Average speed = ?
There is two method two find average speed. In first method, using 3rd equation of motion, we find acceleration.
Then using first equation of motion, we find time
Then using the formula of average velocity, we find average velocity
Second method is very simple
355 m/s